Answer:
x = 7, x = -10
Step-by-step explanation:

Use the quadratic formula.

Solve.
x = 7, x = -10
You can also factor if you want - that is a faster method.
Answer:
See below.
Step-by-step explanation:
The graph of the quadratic equation is a parabola or u shaped graph. It has a vertex at (-1,-3) since h=-1 and k=-3 in the vertex form. It is also facing down since the leading coefficient is negative.
(-2,-2)
Since it has a negative in front of the absolute value, the graph is a downward cone.
Answer: 
Step-by-step explanation:
We can use the Rational Root Test.
Given a polynomial in the form:

Where:
- The coefficients are integers.
-
is the leading coeffcient (
)
-
is the constant term 
Every rational root of the polynomial is in the form:

For the case of the given polynomial:

We can observe that:
- Its constant term is 6, with factors 1, 2 and 3.
- Its leading coefficient is 2, with factors 1 and 2.
Then, by Rational Roots Test we get the possible rational roots of this polynomial:
