Solve each equations check your answer. 0.6v+2.1=4.5 and v=
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The probability of getting a total of 10 will be
<em><u>Explanation</u></em>
The total possible sample spaces for rolling two fair numbered cubes are :
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are total 36 sample spaces.
We need to get a sum of 10 , so the possible sample spaces will be:
(4, 6) , (5, 5) and (6, 4)
That means there are 3 possible sample spaces for getting a sum of 10.
So, the probability of getting a total of 10