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3 years ago

6

How do you solve this problem step by step: (4x+3)+(-7x+5)=?

1 answer:

zloy xaker [14]3 years ago

8 0

$(4x + 3) + ( - 7x + 5)$
Remove unnecessary parenthesis

$4x + 3 + ( - 7x + 5)$
When there is a "+" in front of the parenthesis the expression remains the same

$4x + 3 - 7x + 5$
Collect the like terms by subtracting their coefficients

$(4 - 7)x$
Calculate the difference
$- 3x$
$- 3x + 3 + 5$
Add numbers
$3 + 5 = 8$
Answer:
$- 3x + 8$

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Read 2 more answers

) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.

yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the 0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= $\dfrac{1}{2}$

The length of bits : n = 10

Let X = Number of getting ones.

Then , $X \sim Bin(n=10,\ p=\dfrac{1}{2})$

Binomial distribution formula : $P(X=x)=^nC_x p^x q^{n-x}$ , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , $p=q=\dfrac{1}{2}$

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

$P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}$

$=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}$

$=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})$

$=(\dfrac{1}{2})^{10}(210+252)$

$=(0.0009765625)(462)$

$=0.451171875\approx0.4512$

Hence, the probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

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4 years ago

Easy question:<br> y = -8x<br><br> What is x if you substitute 3 for y?

Artemon [7]

X would be -3/8 or in decimal form 0.375

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3 years ago