Answer:
y = 9
Step-by-step explanation:
Exponent Rule: ![\frac{b^m}{b^n} =b^{m-n}](https://tex.z-dn.net/?f=%5Cfrac%7Bb%5Em%7D%7Bb%5En%7D%20%3Db%5E%7Bm-n%7D)
xⁿ/x³ = x⁶
xⁿ⁻³=x⁶
n = 9
Answer:
2, 1/3 inches in 3/4
basically you multiply the denominator to match the other problem so 1/3 becomes 4/12 and 3/4 becomes 9/12
so there are 2 1/3 inches in 3/4, this is a sort of rough explanation I reccomend going on Khan Academy and looking for something to help you there
Answer:
Average cost per litre of diesel = rs 8.00
Step-by-step explanation:
Amount spent on diesel each year = rs 4000
Price of a litre of diesel in the first year = rs 7.50
Price of a litre of diesel in the second year = rs 8.00
Price of a litre of diesel in the third year = rs 8.50
Average cost per litre of diesel = ![\frac{p_{1} + p_{2} + p_{3} }{n}](https://tex.z-dn.net/?f=%5Cfrac%7Bp_%7B1%7D%20%2B%20p_%7B2%7D%20%2B%20p_%7B3%7D%20%20%7D%7Bn%7D)
where n is the number of years.
Average cost per litre of diesel = ![\frac{7.5 + 8.00 + 8.50}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B7.5%20%2B%208.00%20%2B%208.50%7D%7B3%7D)
= ![\frac{24}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B24%7D%7B3%7D)
= 8
Average cost per litre of diesel is rs 8.00
So that he buys an average of 500 (i.e
) litres every year.
B=number of ticets sold before
a=number of tickets sold after
cost of a ticket=number of tickets times cost per ticket
beforecost=39.95b
aftercost=54.95a
total cost=925000
39.95b+54.95a=925000
total number tickets=20000
b+a=20000
we have
39.95b+54.95a=925000
b+a=20000
multiply second equation by -39.95 and add to first equatin
39.95b+54.95a=925000
<u>-39.95b-39.95a=-799000 +</u>
0b+15a=126000
15a=126000
divide bot sides by 15
a=8400
sub back
b+a=20000
b+8400=20000
minus 8400 both sides
b=11600
11,600 tickets sold before
8400 tickets sold after