If s(x) = x – 7 and t(x) = 4x2 – x + 3, 4(x – 7)2 – x – 7 + 3 4(x – 7)2 – (x – 7) + 3 (4x2 – x + 3) – 7 (4x2 – x + 3)(x – 7)
1 answer:
Answers:
1) (s o t)(x)=4x^2-x-4
2) (t o s)(x)=4(x-7)^2-(x-7)+3
Solution:
1) (s o t)(x)=s(t(x))=s(4x^2-x+3)=(4x^2-x+3)-7=4x^2-x+3-7
(s o t)(x)=4x^2-x-4
2) (t o s)(x)=t(s(x))=t(x-7)=4(x-7)^2-(x-7)+3
(t o s)(x)=4(x-7)^2-(x-7)+3
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