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olchik [2.2K]
2 years ago
6

Finance. Suppose that $ 3 comma 400 is invested at 4.4 % annual interest​ rate, compounded monthly. How much money will be in th

e account in​ (A) 4 ​months? (B) 7 ​years?]
Mathematics
1 answer:
Yuki888 [10]2 years ago
3 0

Answer:

There would be $3,450.14 by the end of 4 months

There would be $4,623.78 by the end of 7 years.

Step-by-step explanation:

We are given the following in the question:

P = 3,400$

r = 4.4% = 0.044

Compounded monthly

Formula:

The compound interest is given by:

A = p\bigg(1+\dfrac{r}{n}\bigg)^{nt}

where A is the amount, p is the principal, r is the interest rate, t is the time in years and n is the nature of compound interest.

a) 4 months

A = 3400\bigg(1+\dfrac{0.044}{12}\bigg)^{4}\\\\A = \$3,450.14

There would be $3,450.14 by the end of 4 months.

b)  7 ​years

t = 7

A = 3400\bigg(1+\dfrac{0.044}{12}\bigg)^{84}\\\\A = \$4,623.78

There would be $4,623.78 by the end of 7 years.

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Answer:

1.33 years.

Step-by-step explanation:

I=PRT

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120/90=T

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3 years ago
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Pls help me solve this question, also include step by step calculation ya. Thks
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\displaystyle\\Answer:\ x=\sqrt{2}\ \ \ \ \ x=-\sqrt{2}\ \ \ \ \ x=\frac{ln5}{2}

Step-by-step explanation:

5x^2-x^2e^{2x}+2e^{2x}=10

Let:\ x^2=t  \ \ \ \ \ e^{2x}=v\\Hence,\\5t-tv+2v^2=10\\5t-tv+2v^2-10=10-10\\5t-tv-10+2v^2=0\\t(5-v)-2(5-v)=0\\(5-v)(t-2)=0\\5-v=0\\5-v+v=0+v\\5=v\\5=e^{2x}

<em>Prologarithmize both parts of the equation:</em>

ln5=lne^{2x}\\ln5=2x*lne\\ln5=2x*1\\ln5=2x\\

<u><em> Divide both parts of the equation by 2:</em></u>

\displaystyle\\x=\frac{ln5}{2}

t-2=0\\t-2+2=0+2\\t=2\\x^2=2\\x=\sqrt{2} \\x=-\sqrt{2}

6 0
1 year ago
You want branliest.more branliest giving out
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Answer:

that is a cute dog

Step-by-step explanation:

1. very fluffy

2. small

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2 years ago
A cylinder has a base area of 44.6 mm2 and a height of 24 mm.
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Read 2 more answers
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