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olchik [2.2K]
3 years ago
6

Finance. Suppose that $ 3 comma 400 is invested at 4.4 % annual interest​ rate, compounded monthly. How much money will be in th

e account in​ (A) 4 ​months? (B) 7 ​years?]
Mathematics
1 answer:
Yuki888 [10]3 years ago
3 0

Answer:

There would be $3,450.14 by the end of 4 months

There would be $4,623.78 by the end of 7 years.

Step-by-step explanation:

We are given the following in the question:

P = 3,400$

r = 4.4% = 0.044

Compounded monthly

Formula:

The compound interest is given by:

A = p\bigg(1+\dfrac{r}{n}\bigg)^{nt}

where A is the amount, p is the principal, r is the interest rate, t is the time in years and n is the nature of compound interest.

a) 4 months

A = 3400\bigg(1+\dfrac{0.044}{12}\bigg)^{4}\\\\A = \$3,450.14

There would be $3,450.14 by the end of 4 months.

b)  7 ​years

t = 7

A = 3400\bigg(1+\dfrac{0.044}{12}\bigg)^{84}\\\\A = \$4,623.78

There would be $4,623.78 by the end of 7 years.

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3 years ago
√9a^2 + √49b - a + √b<br><br><br> a. 2b + 8 √a<br><br> b. 2a - 8 √b<br><br> c. 2a + 8 √b
Firdavs [7]
The correct answer:
______________________________________________________
Explanation:
______________________________________________________
Assuming you mean:

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_________________________________________________________

Note that:  " √(9a²) = 3a " ;

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Combine the "like terms:

   " + 3a − a  =  2a " ;

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________________________________________________________
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8 0
3 years ago
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F(x)=2x+1/x-1 then f^-1(1)​
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<u>Given function:</u>

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