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Anni [7]
2 years ago
9

How do i solve 27=(1/3)^x/2

Mathematics
2 answers:
hram777 [196]2 years ago
7 0

Answer:

x = − 3.63092975

Step-by-step explanation:

babunello [35]2 years ago
3 0

Answer:

-6 ON EDGUNITY

Step-by-step explanation:

You might be interested in
on vacation sally stopped in Algebraville because of their famous pizza house pi-pizza. There they sold pizza by the slice. A sl
Eddi Din [679]

Answer:

600 Cheese and 900 Pepperoni

Step-by-step explanation:

Setup the equation with 2c(Cheese) + 2.5p(Pepperoni) = $3450(Total Made).

In addition to the equation c + p = 1500(Number of pizzas sold)

Using the second equation (c + p = 1500) solve for one of the variables.

Lets use :

  1. p = 1500 - c
  2. Plus this equation into the original equation, 2c + 2.5(1500 - c) = 3450
  3. Distribute 2.5, 2c + 3750 - 2.5c = 3450
  4. Combine like terms -0.5c + 3750 = 3450
  5. Solve for c: c = 600
  6. Plus 600 in for c into any equation ( lets use c + p = 1500)
  7. 600 + p = 1500
  8. P = 900
5 0
2 years ago
Kevin recently accepted a job at a Lucky Seven store 17 miles from his house. Use the
RideAnS [48]

Something is missing there is no given. But here are the given for this question:

Salary = $8.75 per hour

40 hour work week

52 work week per year

5 days of work per week

Gas mileage is 21 miles per gallon

Gas costs is 1.26 per gallon

Average speed is 45 miles per hour

Daily round trip to work and back home is 34 miles

a. Kevin’s annual salary is 8.75 per hour x 40 hour work week x 52 work week per year

= $18,200

b. Kevin will spend on fuel each week:

34 miles daily round trip x 5 day work week divided by 21 miles per gallon x 1.26 per gallon

= $10.20

c. Kevin will spend _ hours on commuting

= 34 miles is the daily round trip x 5 day work week divided by 45 miles average speed per hour

= 3.78 hours

Hope this helps!

7 0
3 years ago
Read 2 more answers
Which of the following sets are subspaces of R3 ?
Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

\to A={(x,y,z)|3x+8y-5z=2} \\\\\to  for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                        =3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)

The set A is not part of the subspace R^3

for point B:

\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon  B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                             =-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0

\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon  B

The set B is part of the subspace R^3

for point C: \to C={(x,y,z)|x

In this, the scalar multiplication can't behold

\to for (-2,-1,2) \varepsilon  C

\to -1(-2,-1,2)= (2,1,-1) ∉ C

this inequality is not hold

The set C is not a part of the subspace R^3

for point D:

\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)

The scalar multiplication s is not to hold

\to for (-4, 1,2)\varepsilon  D\\\\\to  -1(-4,1,2) = (4,-1,-2) ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace R^3

For point E:

\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to  a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\

The  x_1, x_2 is the arbitrary, in which ax_1+bx_2is arbitrary  

\to a(x_1,0,0)+b(x_2,0,0) \varepsilon  E

The set E is the part of the subspace R^3

For point F:

\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon  F \\\\\to  a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))

The x_1, x_2 arbitrary so, they have ax_1+bx_2 as the arbitrary \to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F

The set F is the subspace of R^3

5 0
2 years ago
There are 12 books on a shelf 5 of these books are new the rest are used what is the ratio of new books to used books
tiny-mole [99]

Answer:

5:7

Step-by-step explanation:

Basically you first find the amount of the books are the shelf knowing that you have 5 new books, you subtract the amount of new books from total books. And 5:7 can't be simplified any further making 5:7 the answer.

5 0
2 years ago
Read 2 more answers
I need to know the equations
dem82 [27]
Let l, t, b represent the numbers of lions, tigers, bears, respectively.

2l +3t +3b = 156 . . . . . . . 156 meals per day are supplied
l +t = 3b . . . . . . . . . . . . . . there are 3 times as many great cats as bears
l +t +b = 68 . . . . . . . . . . . there are a total of 68 animals

_____
The last 2 equations tell you
.. 4b = 68
.. b = 17
Subtracting 3 times the last equation from the first gives
.. -l = -48
There are 48 lions, 3 tigers, and 17 bears.
4 0
2 years ago
Read 2 more answers
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