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3 years ago

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Please help me fast!!! Kevin made chili for a football party. He started making the chili at 1:00 P.M. It took 45 minutes to pre

pare and assemble the ingredients. Then, the chili had to simmer for 45 minutes. What time was the chili ready?
Include A.M. or P.M. in your answer.

1 answer:

iVinArrow [24]3 years ago

6 0

Answer:

It was ready at 2:30 pm :)

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4900÷7= slove without a calculator.

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use The Explicit Formula for the Fibonacci Sequence

Step-by-step explanation:

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Dennis arrived at Sullivan's at 10:15am the store opens at 11:00 how long will he have to wait

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He will have to wait 45 minutes

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You have conducted a survey on a number of households and found out how many pets they owned brainly

eduard

Answer:

Using tally marks

Step-by-step explanation:

Missing information;

Number of pets are;

3,0,1,4,4,1,2,0,2,2,0,2,0,1,3,1,2,1,1,3

Find;

Ungroups frequency distribution table

Computation:

<u>Number of pets Tally Frequency</u>

0 IIII 4

1 IIIII I 6

2 IIIII 5

3 III 3

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3 years ago

If a(x)=2x-4 and b(x) =x+2, which of the following expressions produces a quadratic function?

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Answer:

$(ab)(x)$

Step-by-step explanation:

The complete question in the attached figure

we have

$a(x)=2x-4\\b(x)=x+2$

we know that

(ab)(x) is equal to the product of a(x) and b(x)

so

$(ab)(x)=(2x-4)(x+2)$

Applying distributive property

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$(ab)(x)=2x^2+4x-4x-8$

$(ab)(x)=2x^2-8$

This is a quadratic equation

The other expressions not produce a quadratic equation

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3 years ago

A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from thi

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Complete question:

Consider a class of 20 students consisting of 5 sophomores, 8 juniors, and 7 seniors. A math instructor assigns a group project in each of the scenarios below, the instructor selects 5 consecutive students from this class, keeping track (in order) of the level of the student that he gets.

1a. How many possible outcomes are in the sample space S? (An outcome is a 5- tuple of students.)

Let A2 denote the event that exactly 2 of the selected students are sophomore, A5 denote the event that exactly 5 of the selected students are the juniors, and A4 denote the event that exactly 4 of the selected students are seniors.

1b. Find the probabilities of each of these three events. A2, A5, A4

1c. Do the events A2, A5, A4 constitute a partition of the sample space?

Answer:

Given:

n = 20

a) The possible outcome in the sample space,S, =

ⁿCₓ = ²⁰C₅

$= \frac{20!}{(20-5)! 5!)}$

$= \frac{20*19*18*17*16}{5*4*3*2*1}$

= 15504

b) probabilities of A2, A5, A4

P(A2) = ⁵C₂ / ²⁰C₂

$= \frac{20}{320} = \frac{1}{19}$

P(A5) = ⁸C₅ / ²⁰C₅

$= \frac{56}{15540} = \frac{7}{1938}$

P(A4) = ⁷C₄ / ²⁰C₄

$= \frac{35}{4845} = \frac{7}{969}$

c) No,the events A2, A5, A4, do not comstitute a partition of the sample space. i.e P(A2)+P(A5)+P(A4) ≠ 1

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3 years ago