Direct variation should be called linear variation.
In this case, the answer is B.
A has the quadratic variation, C has the inverse variation, D has the cubic variation
Answer:
In the image below
Step-by-step explanation:
Split the second term in 9s^2 - 36s + 35 into two terms
9s^2 - 15s - 21s + 35
Factor out common terms in the first two terms, then in the last two terms
3s(3s - 5) - 7(3s - 5)
Factor out the common term 3s - 5
<u>(3s - 5)(3s - 7) </u>
Answer: sin
= ±
Step-by-step explanation:
We very well know that,
cos2A=1−2sin²A
⟹ sinA = ±
As required, set A =
& cos a=
,thus we get
sin
=±
∴ sin
=±
= ±
since ,360° <
<450°
,180° <
<225°
Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.
hope it helped!