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Olenka [21]
3 years ago
14

Given the range of the function find the corresponding domain. f(x)=7x-1 Range {-2,0,4,8}

Mathematics
1 answer:
LenaWriter [7]3 years ago
8 0

f(x) = 7x - 1

-2 = 7x - 1

-2 + 1 = 7x

-1 = 7x

x = -1/7

0 = 7x - 1

1 = 7x

x = 1/7

4 = 7x - 1

4 + 1 = 7x

5 = 7x

x = 5/7

8 = 7x - 1

8 + 1 = 7x

9 = 7x

x = 9/7

So the domain is

Domain = {-1/7, 1/7, 5/7, 9/7}

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givi [52]
2) if it refers to the gray shaded boxes out of all the boxes, then count them 5 rows × 5 columns = 5×5 = 25
The total is 10 rows × 10 columns = 10×10 = 100
Fraction: 25/100 ->> divide both by 25 = 1/4
Decimal: 0.25
Ratio: 25 grey boxes: (100-25) white boxes
= 25:75 ->> divide both by 25 = 1:3
Percent: means "out of 100" so we know it's 25 out of 100 = 25%

3) 27 is 75% of what??
let's make x = what we don't know
\frac{part}{whole}  =  \frac{percent}{100}  \\ \frac{27}{x}  =  \frac{75}{100}
Now cross-multiply: multiply top left with bottom right and make equal to the bottom left times the top right
27×100 = 75x
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5 0
3 years ago
How do i solve this?<br> how many ways can you choose 3 dishes from a menu of 8?
JulijaS [17]
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7 0
3 years ago
What is the value of y in the figure if x = 30°?<br> y =
QveST [7]

Answer:

y is 150

Step-by-step explanation:

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hope this helped!

7 0
2 years ago
Read 2 more answers
Band practice lasted 4/5 of an hour. 2/3 of that time was spent marching. How many minutes were they marching?
GuDViN [60]

Answer: They were marching for 32 minutes.

Step-by-step explanation: If you multiply the 4/5 times by 60 minutes (1 hour), then you will get 48 minutes. 48 minutes is the time of the band practice. Once you get that, then multiply that by 2/3 to get the amount of minutes marching. Once you multiply 2/3*48, you will get 32, which is how many minutes they were marching during band practice.

8 0
3 years ago
Given f(x)=x+2 and h(x)=1/x-1 evaluate the following function at x=2​ <br><br>[h(x)]^2/f(x)
dlinn [17]

Answer:

\frac{1}{4}

Step-by-step explanation:

Substitute x = 2 into both h(x) and f(x)

h(2) = \frac{1}{2-1} = 1 ⇒ (h(2))² = 1

f(2) = 2 + 2 = 4

Hence

\frac{h(x)^2}{f(x)} when x = 2

= \frac{1}{4}

7 0
3 years ago
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