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jek_recluse [69]
3 years ago
7

Multiply the following polynomials. (3x2-5x-4)(2x-7)

Mathematics
1 answer:
Gelneren [198K]3 years ago
7 0
The 1st 1 I think is 26 and the 2nd one should be -14
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An official playing field (including end zones) for the Indoor Football League has a length 29 yd longer than its width. The per
Dennis_Churaev [7]

Answer:

An official playing field (including end zones) for the Indoor Football League has a length 29 yd longer than its width. The perimeter of the rectangular field is 158 yd. Find the length and width of the field

Step-by-step explanation:

7 0
3 years ago
On his bike, Jason can travel 8 miles in 50 minutes.
d1i1m1o1n [39]

Answer:

24 miles

Step-by-step explanation:

50 minutes = 8 miles

100 miles = 16 miles

150 minutes = 24 miles

4 0
2 years ago
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What is the factorization of the polynomial below?<br> 5x2 - 35x + 60
natita [175]

Answer:

5(x-3)(x-4)

Step-by-step explanation:

5x^2-35x+60

Start by factoring out a 5:

5(x^2-7x+12)

We need to find two integers that have a product of 12, and a sum of -7:

(-3)(-4)=12

-3-4=-7

We can split -7x into -3x and -4x

5(x^2-3x-4x+12)

Factor each half separately:

5[x(x-3)-4(x-3)]

Since x and -4 are both being multiplied by x-3, we can combine them:

5(x-3)(x-4)

7 0
2 years ago
Solve the equation x/4 - 7 = y for x
expeople1 [14]

Answer:

x = 4y + 28

Step-by-step explanation:

x/4 - 7 = y

+7              +7

x/4 = y + 7

× 4             × 4

x = 4y + 28

7 0
3 years ago
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Please help me Algebra 1
Oduvanchick [21]

Answer:

a.  \sqrt{x^n} = x^\frac{n}{2}

b. \sqrt{x^n}  = x^\frac{(n-1)}{2}\sqrt{x}

Step-by-step explanation:

a) When <em>n </em>is even, then it is divisible by 2. Because of this, you can write:

  • \sqrt{x^n} = (x^n)^\frac{1}{2}
  • \sqrt{x^n} = x^\frac{n}{2}

b) When <em>n </em>is odd, then <em>n - 1 </em> is even. This would make it divisible by 2, and there would be a remainder of 1, so we can write:

  • \sqrt{x^n} = (x^n^-^1^+^1) ^\frac{1}{2}
  • \sqrt{x^n} = (x^n^-^1 × x)^\frac{1}{2}
  • \sqrt{x^n} = x^\frac{(n-1)}{2} × x^\frac{1}{2}
  • \sqrt{x^n}  = x^\frac{(n-1)}{2}\sqrt{x}
8 0
2 years ago
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