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3 years ago

Solve for U -8u = - 16/3

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

4 0

Answer:

u = 2/3

Step-by-step explanation:

Simply divide both sides by -8:

u = (-16/3)/-8

If you don't have a calc, use KCF:

u = (-16/3)(-1/8)

u = 16/24

u = 2/3

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Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

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Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

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3. $h(x)=\frac{3x-5}{x^2-5x+7}$

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Hence, function h is defined for all real values.

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The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

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The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

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$x^2+x+29=0$

It cannot be factorize .

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7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

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The denominator of m is defined for all real values of x.

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