Total Number of cards = 4 + 6 = 10
Number of Football cards = 4
Number of Basketball cards = 6
Probability of choosing a football card = 4/10 = 0.4
Since this card is replaced, the total number of cards will remain the same.
Probability of selecting a basketball card = 6/10 = 0.6
Since, the two events are independent, the probability of selecting a football and a basketball card will be the product of two probabilities we calculated.
Thus, probability of selecting a football card and then a basketball card = 0.4 x 0.6 = 0.24
Answer:
Step-by-step explanation:
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Good evening ,
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The right answer is D
We should rotate the R point 3/4 a circle clockwise so it falls on D point.
:)
Answer:
p=3 , q=1 , r=2
Step-by-step explanation:
1176=2*2*2*3*7*7
1176=(2^3)*(3^1)*(7^2)
given that 1176 = (2^p)*(3^q)*(7^r)
Comparing Equation 1 & 2
we get p=3 , q=1, r=2
8x+3=43
-3 -3
8x=40
/8 /8
X=5
