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MArishka [77]
3 years ago
10

Four sets of data are shown in box-and-whisker plots. Which set has the largest 3rd Quartile value?

Mathematics
1 answer:
Airida [17]3 years ago
7 0

Answer:

I think that is A.

Step-by-step explanation:

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The LCM and the GCF of two numbers is 120 and 8 respectively. If the first number is 24, find the other number​
Ivanshal [37]

Answer: The other no. is 5

Step-by-step explanation: Let the other no. be x

x = LCM/First no.

x = 120/24 = 5

The other no. is 5

7 0
3 years ago
How do I find the equation for the line?
GrogVix [38]

Answer:

The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.

7 0
2 years ago
Determine the equation of quadratic function represented by the table of value below.
Svetllana [295]

Answer:

A

Step-by-step explanation:

The general rule for the quadratic function is

y=ax^2+bx+c

Use the data from the table:

y(0)=6\Rightarrow 6=a\cdot 0^2+b\cdot 0+c\\ \\y(1)=4\Rightarrow 4=a\cdot 1^2+b\cdot 1+c\\ \\y(-1)=10\Rightarrow 10=a\cdot (-1)^2+b\cdot (-1)+c

We get the system of three equations:

\left\{\begin{array}{l}c=6\\ \\a+b+c=4\\ \\a-b+c=10\end{array}\right.

From the first equation

c=6, then

\left\{\begin{array}{l}a+b=-2\\ \\a-b=4\end{array}\right.

Add these two equations:

a+b+a-b=-2+4\\ \\2a=2\\ \\a=1

So,

b=-2-a=-2-1=-3

The quadratic function is

y=1\cdot x^2-3x+6\\ \\y=x^2-3x+6

6 0
3 years ago
Tom invests $10,000 in a savings account that offers 3.5 percent interest, compounded continuously.
Elena-2011 [213]
For the answer to the question above, I'm not sure if your question is incomplete or the data on your question is incomplete but I'll answer it anyway because some data are provided.

10,000(1+.035)^10
10,000(1.043)^10
10,000(<span>1.41059876062)
=</span><span>14,105.99

</span>14,105.99/.035
=<span>40, 3028.21</span><span>
I still hope that this helps</span>
5 0
3 years ago
Describe each of the following transformation that maps the figures described below. Be specific by naming lines of reflection,
Flura [38]

Answer:

Part A: Figure 1 → Figure 4

Rigid Transformation

Equivalent to a reflection about the origin, or a rotation of 180° clockwise or anticlockwise about the origin which are types of rigid transformation

Part B: Figure 2 → Figure 5

Similarity transformation

Figure 5 is Figure 2 dilated by a scale factor of 1/2, which is a form of a similarity transformation

Step-by-step explanation:

Part A: Figure 1 → Figure 4

The coordinates of the vertices of the preimage are;

(5, 10), (2, 4), (9, 2)

The coordinates of the vertices of the image are;

(-9, -2), (-2, -4), (-5, -10)

Which is equivalent to a reflection about the origin, or a rotation of 180° clockwise or anticlockwise about the origin

Part B: Figure 2 → Figure 5

The coordinate points of figure 2 are;

(-9, 2), (-5, 10), and (-2, 4)

The coordinate points of figure 5 are;

(1, 2), (2.5, -1), and (4.5, 3)

The lengths of the sides of figure 2 are;

√((10 - 2)² + ((-5) - (-9))²) = 4·√5

√((10 - 4)² + ((-5) - (-2))²) = 3·√5

√((2 - 4)² + ((-9) - (-2))²) = √53

The lengths of the sides of figure 5 are;

√(((-1) - 2)² + (2.5 - 1)²) = (3·√5)/2

√((4.5 - 2.5)² + (3 - (-1))²) = 2·√5

√((4.5 - 1)² + (3 - 2)²) = (√53)/2

Therefore. Figure 5 is Figure 2 dilated by a scale factor of 1/2

Therefore, given that the sides of Figure 2 and Figure 5 are rotated by 180°

We have;

Figure 5 is obtained as follows;

1) The rotation of figure 2 by 180°, clockwise or anticlockwise about the origin to get;

(-9, 2), (-5, 10), and (-2, 4) → (9, -2), (5, -10), and (2, -4)

2) The image is translated left by 1 blocks and up by 6 blocks as follows;

(9, -2), (5, -10), and (2, -4)  → (8, 4), (4, -4), and (1, 2)

3) The image is then dilated by a scale factor of 1/2  with a center of dilation of (1, 2) to get;

Preimage (8, 4), (4, -4), and (1, 2) → Image (1, 2), (2.5, -1), and (4.5, 3).

8 0
3 years ago
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