Please help i don’t know what answers apply

Mathematics

2 answers:

drek231 [11]3 years ago

6 0

I agree with the fist person answer

dalvyx [7]3 years ago

4 0

Answers are B, C, and D

If Q = 33, then the two slopes are both 33. As long as the y intercepts are different, then the two lines will be parallel leading to no intersections. No intersections means no solutions.

Note: Choice A leads to infinitely many solutions as we'll have identical copies of the same expression on each side (33x+25 = 33x+25). This is why we can rule choice A out.

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The measure of angle B is 839, and the measure of angle C is 420.

Usimov [2.4K]

Answer: C. 55 degrees

8 0

3 years ago

Find the volume of the cone

irina1246 [14]

Answer:

The volume of the cone is 12936 cubic mm.

Step-by-step explanation:

Given

Circumference of base = 132 mm

Height of the cone = 28 mm

Solution

Formula of circumference = $2\pi r$ = 132 mm

$\therefore\ r= \frac{132}{2 \pi } = 21 mm$

Now volume of cone = $\frac{1}{3} \times\pi \times r^{2} \times h$

on substituting the value of r and h we get ;

$\frac{1}{3}\times\frac{22}{7} \times21\times21\times28= 12936\ mm$

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3 years ago

Simplify ( 8∙4∙2 8∙7 )^2 × ( 8 0 7−3 )^3 × 7 −9 .

stich3 [128]

$\bf ~\hspace{7em}\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
~\hspace{4.5em}
a^n\implies \cfrac{1}{a^{-n}}
~\hspace{4.5em}
\cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\left( \cfrac{8\cdot 4\cdot 2}{8\cdot 7} \right)^2\times \left( \cfrac{8^0}{7^{-3}} \right)^3\times 7^{-9}\implies \left( \cfrac{8\cdot 8}{8\cdot 7} \right)^2\times \left( \cfrac{1\cdot 7^3}{1} \right)^3\times \cfrac{1}{7^9}$

$\bf \left( \cfrac{8}{8}\cdot \cfrac{8}{7} \right)^2\times (7^3)^3\times \cfrac{1}{7^9}\implies \left( \cfrac{8}{7} \right)^2\times 7^{3\cdot 3}\times \cfrac{1}{7^9}\implies \cfrac{8^2}{7^2}\times \cfrac{7^9}{7^9}
\\\\\\
\cfrac{8^2}{7^2}\implies \cfrac{64}{49}$