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zheka24 [161]
2 years ago
5

You install 638 feet of fencing along the perimeter of a rectangular yard. The width of the yard is 152 feet. What is the length

of the yard?
Mathematics
1 answer:
vovikov84 [41]2 years ago
6 0

The length is 486

Step-by-step explanation:

638 subtract 152

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Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
Use substitution to solve the system of equations.
adelina 88 [10]

Answer:

(2, -5)

Step-by-step explanation:

x is defined by the first equation as x = -3y – 13.  Substitute  -3y – 13 for x in the second equation:

2( -3y – 13) + 2y = -6.

Performing the indicated multiplication, we get:

-6y - 26 + 2y = -6

Combining like terms results in:

-4y = 20, so that y = -5

Using the first equation, we find x for y = -5:

x = -3(-5) - 13 = 2

The solution is thus (2, -5) (Answer C)

5 0
3 years ago
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Multiply the additive inverse of (-7/8) by the reciprocal of (5 1/2)​<br><br>PLEASE HELP!
EleoNora [17]

Answer:

\bold {$\dfrac{7}{44}$}

Step-by-step explanation:

<h3> Reciprocal:</h3>

    \sf \text{The reciprocal of any number $\dfrac{a}{b}$ is given by $\dfrac{b}{a}$}\\\\5\dfrac{1}{2}=\dfrac{11}{2}\\\\\text{Reciprocal of $\dfrac{11}{2}$  = $\dfrac{2}{11}$}

<h3>Additive inverse:</h3>

 \text{Additive inverse of $\dfrac{-7}{8}$=$\dfrac{7}{8}$}

        Now multiply,

          \sf \dfrac{7}{8}*\dfrac{2}{11}=\dfrac{7}{4}*\dfrac{1}{11}\\

                      =\dfrac{7}{44}

7 0
1 year ago
What two numbers is 94 between
levacccp [35]
94 is between 93 and 95
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When a 63 N object falls to the ground from a height of 3.7 m. How much work is done by the force of
jek_recluse [69]

Answer:

A lot actually, gravity is a force of energy which energy is used to do work.

Step-by-step explanation:

7 0
2 years ago
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