Considering the answers;
A. are still sibling species
B. shared a common ancestor more recently with each other than either did with the other two species
C.May merge into a single species if their hybrids remain fertile over the course of many generations.
D. A and B only
E. A, B, and C
The answer will be E.
If no other species can hybridize, then species W and Y are still sibling species, shared a common ancestor more recently with each other than either did with the other two species and also may merge into a single species if their hybrids remain fertile over the course of many generations.
Ok, so I wrote these out just to make it a little bit easier for you to understand what I am about to explain.
So for the first one you have two different traits that can be inherited- having freckles or having no freckles, F and f respectively. The dominant trait (or having freckles) is shown by the capital F, and is almost always expressed over the recessive trait, or the lowercase f. So, for example, if you have a genotype of Ff, the trait having freckles will show up instead of not having freckles. The only way that you could have the trait of no freckles show up is if there are two recessive alleles for having no freckles, or ff. In this case, you have two parents who are both heterozygous for the trait of having freckles, so in other words the mother has Ff and the father has Ff. Each parent passes down one allele to the offspring, so since you are breeding Ff and Ff, you should result in having the possible genotypes of FF, Ff, Ff, and ff. This means that there is a 25% chance that the offspring will be homozygous for having freckles, a 50% chance that the offspring will be heterozygous for having freckles and a 25% chance that they would be homozygous for having no freckles, or a 1:2:1 ratio.
Incomplete dominance is a little bit different that just a normal monohybrid cross. Instead of just the dominant gene showing up in a heterozygous genotype, both traits show up. So like the question says, if a homozygous red flower plant was crossed with a homozygous white flower plant, their offspring would not just be white or red, they would be pink because it is a mixture of white and red. So then if you crossed the heterozygous, or Rr plants, the result would be a 25% chance of getting a homozygous RR red plant, a 50% chance of getting a pink Rr plant, and a 25% chance of getting a white rr plant, or another 1:2:1 ratio.
Sorry for the wordy answer, but hopefully this helps you understand this a little better :)
Answer:
Quadrat method is used for estimating the number of individuals in an area. In this method, a large square area on the ground or water surface is marked, call it an enclave. The number of animals present in this enclave is counted. Then by assuming that the animals are less migratory and are uniformly distributed, their number for a large area is estimated by the use of unitary method of calculation. Example a 4 square feet area has 2 snails, then a 1000 square feet area will have (1000 x 2)/4, i.e, 500 snails in it. Fishes can be counted using this method only if they are confined in a small water body like a lake or a pond. Rivers are flowing so the fishes may move along its length which can give us an underestimate or an overestimate of their numbers. Sea has its depth and huge area, and fishes can be moving randomly in it. Hence this method will not work for river and sea fishes.
Explanation:
Hope this helps :D
Answer:
The number of individuals displaying each phenotype in both the current generation and the offspring.
Explanation: