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SSSSS [86.1K]
3 years ago
14

Simplify the following: 6x - 6y + 4x - 3y - 5x + 7x

Mathematics
1 answer:
goblinko [34]3 years ago
3 0
12x-9y is the simplified answer
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Joshua and 23 friends earned a total of $864 working during the summer.They each earned the same amount.How much did each person
Korolek [52]

Answer:

each person earned 36 dollars

Step-by-step explanation:

864 divided by 24

36

7 0
3 years ago
How do you solve<br> -2 over 9
dlinn [17]

Answer: -0.22222222...

Step-by-step explanation:

-2 over 9 can be written as -2/9

So that’s basically -2 divided by 9. If you’d do long division properly, you should get -0.22222222...

7 0
3 years ago
Samira bought 156 ounces of trail mix.She wants to divide the amount equally into 24 portions.How many ounces of trail mix will
expeople1 [14]

Answer:

6.5

Step-by-step explanation:

3 0
3 years ago
Evaluate the expression for a = 5, b = 11, and c = 3. 2a + 2c(b − 5) A. 64 B. 46 C. 54 D. 163
Artemon [7]

2a +2c(b-5)

substitute a=5 b=11 c=3

2(5) +2(3) (11-5)

10+6(6)

10+36

46

Choice B


8 0
2 years ago
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
3 years ago
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