D) 28 is the right answer
find the attachments for the details
Plug 8 into the equation and divide it by that equation but with 5 plugged in
Answer/Step-by-step explanation:
The following steps to solve equation given by join are shown below including the property of numbers applied for each reasons:
4(2a + 3) = -3(a - 1) + 31 - 11a ----› Given
Apply the distributive property to open the parentheses
4*2a + 4*3 = -3*a -3*-1 + 31 - 11a
8a + 12 = -3a + 3 + 31 - 11a ----› Distributive property
Combine like terms together
8a + 12 = 3 + 31 -3a - 11a
8a + 12 = 34 - 14a ---› Combining like terms
Add 14a to both sides
8a + 12 + 14a = 34 - 14a + 14a
22a + 12 = 34 ----› Addition property
Subtract 12 from both sides
22a + 12 - 12 = 34 - 12
22a = 22 ----› subtraction property of equality
Divide both sides by 22
22a/22 = 22/22
a = 1 ----› Division property of Equality
Answer:
No, mn is not even if m and n are odd.
If m and n are odd, then mn is odd as well.
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Proof:
If m is odd, then it is in the form m = 2p+1, where p is some integer.
So if p = 0, then m = 1. If p = 1, then m = 3, and so on.
Similarly, if n is odd then n = 2q+1 for some integer q.
Multiply out m and n using the distribution rule
m*n = (2p+1)*(2q+1)
m*n = 2p(2q+1) + 1(2q+1)
m*n = 4pq+2p+2q+1
m*n = 2( 2pq+p+q) + 1
m*n = 2r + 1
note how I replaced the "2pq+p+q" portion with r. So I let r = 2pq+p+q, which is an integer.
The result 2r+1 is some other odd number as it fits the form 2*(integer)+1
Therefore, multiplying any two odd numbers will result in some other odd number.
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Examples:
- 3*5 = 15
- 7*9 = 63
- 11*15 = 165
- 9*3 = 27
So there is no way to have m*n be even if both m and n are odd.
The general rules are as follows
- odd * odd = odd
- even * odd = even
- even * even = even
The proof of the other two cases would follow a similar line of reasoning as shown above.
