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inysia [295]
3 years ago
5

Square root of 36 rounded to the nearest hundredth

Mathematics
1 answer:
Digiron [165]3 years ago
4 0
The square root of 36 is 6.00.  I know this because six squared (6*6) is 36.
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The area of a parallelogram is 31.5 ft and the height is 6.3 ft. What is the length of the base?
makvit [3.9K]
The base is 5 because when you divide 31.5 by 6.3 it's 5
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List the values that make up the domain of this relation.
balandron [24]

\bf (\stackrel{\downarrow }{5},3),(\stackrel{\downarrow }{2},-7),(\stackrel{\downarrow }{1},-8),(\stackrel{\downarrow }{8},3)\qquad \quad \stackrel{\textit{the domain is always the set of the 1st coordinate}}{(5,2,1,8)}

6 0
3 years ago
Help! I don't understand this
Murljashka [212]

The area of your circle is about 530.93 m

The diameter of your circle is 26 m, just multiply your radius by 2

The circumference of the circle is about 81.68


The equation to finding the area is

pi x r x 2

3.14 times 13 times 2

The equation to finding the diameter

r x 2

radius times 2

The equation for finding circumference

pi x d

3.14 times 26

Let me know if im wrong, otherwise I want brainliest, PLEASE!!

8 0
3 years ago
How much does 3 go into 16
sveta [45]
5 times that’s how much
3 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!
Nitella [24]

Answer:

The radius of a sphere is 2 millimeters

The surface area of a sphere is 50.24 square millimeters.

The circumference of the great circle of a sphere is 12.56  millimeters.

Step-by-step explanation:

<u><em>Verify each statement</em></u>

case A) The radius of a sphere is 8 millimeters

The statement is false

we know that

The volume of the sphere is equal to

V=\frac{4}{3}\pi r^{3}

we have

V=100.48/3\ mm^{3}

\pi =3.14

substitute and solve for r

100.48/3=\frac{4}{3}(3.14)r^{3}

r^{3}=(100.48)/(4*3.14)

r=2\ mm    

case B) The radius of a sphere is 2 millimeters

The statement is True

(see the case A)

case C) The circumference of the great circle of a sphere is 9.42 square millimeters  

The statement is false

The units of the circumference is millimeters not square millimeters

The circumference is equal to

C=2\pi r

we have

r=2\ mm  

\pi =3.14

substitute

C=2(3.14)(2)

C=12.56\ mm

case D) The surface area of a sphere is 50.24 square millimeters.

The statement is True

Because

The surface area of the sphere is equal to

SA=4\pi r^{2}

we have

r=2\ mm  

\pi =3.14

substitute

SA=4(3.14)(2)^{2}

SA=50.24\ mm^{2}

case E)  The circumference of the great circle of a sphere is 12.56  millimeters.  

The statement is true

see the case C

case F) The surface area of a sphere is 25.12 square millimeters

The statement is false

because the surface area of the sphere is SA=50.24\ mm^{2}

see the case D

7 0
3 years ago
Read 2 more answers
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