Given y=2x^2-6x+3. X=-1
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It is parallel, which means that the new line should have the same slope of the given line 
and the slope is the coefficient of x
so the slope = -5/4
in order to solve this problem we have to know the equation of the slop
where (x1,y1) is the point by which the new line passes through
-5(x-1)=4(y+4)
-5x +5=4y+16 (by subtracting 16 from both sides)
-5x -11= 4y (divide both sides by 4)
y=
and the slope is the coefficient of x
so the slope = -5/4
in order to solve this problem we have to know the equation of the slop
where (x1,y1) is the point by which the new line passes through
-5(x-1)=4(y+4)
-5x +5=4y+16 (by subtracting 16 from both sides)
-5x -11= 4y (divide both sides by 4)
y=