-5y + 8 = -3y + 10
We need to get y on one side.
Add 3y to both sides.
-2y + 8 = 10
We need to get 2y by itself.
Subtract 8 from both sides.
-2y = 2
Divide both sides by -2 to solve for y.
y = -1

I hope this helps!

8 0

3 years ago

Read 2 more answers

8x to the 2nd power +2x-3=0

Papessa [141]

Answer:

x= 1/2 and -3/4

Step-by-step explanation:

By using factorization, we can solve this equation.

8x^2+2x-3=0

Factor:

(2x-1)(4x+3)=0

Solve:

2x-1=0

2x=1

x=1/2

Solve again:

4x+3=0

4x=-3

x=-3/4

Hope this helped

5 0

3 years ago

The sum of mZAOB and mZBOC IS 128º. Find the measure of ZBOC.

amm1812

128 - 33 = 95
Answer C. 95

4 0

3 years ago

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If you want to be 95% confident of estimating the population mean to within a sampling error of plus or minus3 and the standard

Aleksandr [31]

Answer:

The sample size required is at least 171

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What sample size is required?

A samle size of at least n is required, in which n is found when $M = 3, \sigma = 20$

$M = z*\frac{\sigma}{\sqrt{n}}$

$3 = 1.96*\frac{20}{\sqrt{n}}$

$3\sqrt{n} = 20*1.96$

$\sqrt{n} = \frac{20*1.96}{3}$

$(\sqrt{n})^{2} = (\frac{20*1.96}{3})^{2}$

$n = 170.7$

Rouding up

The sample size required is at least 171

5 0

3 years ago