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andrew-mc [135]
3 years ago
7

Please help :(( I’m having a hard time with these

Mathematics
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

1

Step-by-step explanation:

what you do on one side of the equal sign, you do to the other

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12 pots cost $27 . what is the cost of 8 pots?​
Alborosie

Answer:

$18

Step-by-step explanation:

you divide 27/12= 2.25 this gives you the price for one.

then you multiply 8 × 2.25 = $18

$18 dollars is the price for 8 pots

6 0
3 years ago
Which of the following is the the correct factorization of this trinomial.
sergey [27]
-3x^2-10x-8 = - (3x^2 +10x+8 ) = - (3x^2 +6x +4x+8) =\\ \\=-[3x(x+2)+4(x+2)]= - (3x+4) (x+2) \\ \\Answer : \ c)\ \ \ -(3x+4)(x+2)


6 0
3 years ago
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Sarah is the oldest out of here four sisters. Her youngest sister is half her age. The 2 other sisters are twin and are 2 years
marusya05 [52]
Sarah is 14
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7 0
3 years ago
Can someone please answer. There is a picture. There is only one question. Thank you so much
KatRina [158]
Hello,

Answer A

(x-x0)²+(y-y0)²=r²
7 0
3 years ago
work for a publishing company. The company wants to send two employees to a statistics conference. To be​ fair, the company deci
Yuki888 [10]

Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the​ conference is 0.10.

(c) The probability that Clarice attends the​ conference is 0.40.

(d) The probability that John stays​ home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (<em>M</em>), Roberto (<em>R</em>), John (<em>J</em>), Dominique (<em>D</em>) and Clarice (<em>C</em>) works for the company.

The company selects two employees randomly to attend a statistics conference.

(a)

There are 5 employees from which the company has to select two employees to send to the conference.

So the total number of ways to select two employees is:

{5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10

The 10 possible samples are:

MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event <em>E</em> is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = Total number of outcomes.

The variable representing the selection of  Roberto and John is, <em>RJ</em>.

The favorable number of outcomes to select Roberto and John is, 1.

The total number of outcomes to select 2 employees is 10.

Compute the probability that Roberto and John attend the​ conference as follows:

P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10

Thus, the probability that Roberto and John attend the​ conference is 0.10.

(c)

The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

Compute the probability that Clarice attends the​ conference as follows:

P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40

Thus, the probability that Clarice attends the​ conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

n (J') = MR, MD, MC, RD, RC, DC

Compute the probability that John stays​ home as follows:

P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60

Thus, the probability that John stays​ home is 0.60.

4 0
3 years ago
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