Answer:
The mean for the second week is $2 less than the first and in percentage it is 22% less.
Step-by-step explanation:
The mean is given by the sum of all individual values divided by the number of values. For the first week the sum is:
sum1 = 6.5 + 8 + 7.25 + 13.5 + 9.75
sum1 = 45
Since she spent 10 less in the second week the sum is:
sum2 = sum1 - 10 = 45 - 10 = 35
The mean for each week is:
mean1 = sum1/5 = 45/5 = 9
mean2 = sum2/5 = 35/5 = 7
difference = mean1 - mean2 = 9-7 = 2
difference(%) = [2/9]*100 = 0.22*100 = 22%
The mean for the second week is $2 less than the first and in percentage it is 22% less.
<h2><u>Question</u><u>:</u><u>-</u></h2>
A fruitseller bought 50kg of the fruits. He sold 30kg of fruits for the cost price of 35kg of fruits and he sold the remaining quantity for the cost Price of 18kg of fruits. calculate his profit or loss percent in the total transaction.
<h2><u>Answer</u><u>:</u><u>-</u></h2>
let the cost price be 50x
→he sells 30kg of fruits on it's CP of 35 kg
→CP of 30kg fruits = 30x
→SP of 35kg fruits = 35x
→remaing fruits are 20kg
→he sells 20kg of fruits on CP of 16kg
→CP of 20kg fruits = 20x
→SP of 20kg fruits = 16x
→total CP is = 50x
→total SP is = (35 + 16) = 51x
→SP > CP (it means profit)
→profit = SP-CP
→ 51-50
→ 1
<h2 /><h2><u>Now,</u></h2>
→ Profit% = gain/CP × 100
→ Profit% = 1/50 × 100
→ 2%
Hence the fruit seller had a profit% of 2%.
I think it has the same DNA as its parent
Hi!
The fully factored form of this equation is (3x+2)²
Answer: A
Step-by-step explanation:
