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mrs_skeptik [129]
2 years ago
10

2. Which memory locations are assigned by the hashing function h(k) = k mod 101 to the records of insurance company customers wi

th these Social Security numbers? a) 104578690 b) 432222187 c) 372201919 d) 501338753
Mathematics
1 answer:
jeyben [28]2 years ago
5 0

Answer:

Memory Locations assigned

a) 58 b) 60 c) 52 d) 3  

Step-by-step explanation:

We are given that:

h(k) = k mod 101

To find the memory location, we need to evaluate the modulus value abbreviated as mod, k modulo n, which returns the value of remainder when k is divided by 101.

a) 104578690

104578690 mod 101 = 58

b) 432222187

432222187 mod 101 = 60

c) 372201919

372201919 mod 101 = 52

d) 501338753

501338753 mod 101 = 3

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25=b^2 = 49

49-25=b^2

49-25=14

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4 0
3 years ago
Warmup/Reflection- necessary for attendance
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Answer:

x = 7

Step-by-step explanation:

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Answer:

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6 0
2 years ago
P(x)= 3x^3-5x^2-14x-4
nexus9112 [7]
   
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\displaystyle\\&#10;\text{Verification}\\\\&#10;3x^3-5x^2-14x-4=\\\\&#10;=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\&#10;=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\&#10;=-\frac{6}{9}+\frac{14}{3}-4=\\\\&#10;=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\&#10; =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\&#10;\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\&#10;\Longrightarrow~~~P(x)~\vdots~(3x+1)


\displaystyle\\&#10;3x^3-5x^2-14x-4=0\\&#10;~~~~~-5x^2 = x^2 - 6x^2\\&#10;~~~~~-14x =-2x-12x \\&#10;3x^3+x^2 - 6x^2-2x-12x-4=0\\&#10;x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\&#10;(3x+1)(x^2-2x -4)=0\\\\&#10;\text{Solve: } x^2-2x -4=0\\\\&#10;x_{12}= \frac{-b\pm  \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm  \sqrt{4+16}}{2}=\frac{2\pm  \sqrt{20}}{2}=\frac{2\pm  2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\&#10;x_1 =1+\sqrt{5}\\&#10;x_2 =1-\sqrt{5}\\&#10;\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}



7 0
3 years ago
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