Answer:
<u>Calvin withdraws $ 60 each week</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Calvin's account balance difference than 8 weeks ago = - $ 360
Weekly amount Calvin deposits = $ 15
Number of weeks to compare = 8
2. What was his average withdrawal each week?
Let's calculate the weekly average withdrawal this way:
Weekly average withdrawal = [Calvin's account balance difference than 8 weeks ago - (Weekly amount Calvin deposits * Number of weeks to compare)]/Number of weeks to compare
Replacing with the values given:
Weekly average withdrawal = [-360 - (15 * 8)]/8
Weekly average withdrawal = -360 - 120 / 8
Weekly average withdrawal = -480 / 8
<u>Weekly average withdrawal = -60</u>
<u>Calvin withdraws $ 60 each week</u>
Answer:
17
Step-by-step explanation:
There are 146 - 84 = 62 girls
ratio is 84:62
simplifies to 42:31
The answer is x=2 that is the answer
Answer:
Algorithm
Start
Int n // To represent the number of array
Input n
Int countsearch = 0
float search
Float [] numbers // To represent an array of non decreasing number
// Input array elements but first Initialise a counter element
Int count = 0, digit
Do
// Check if element to be inserted is the first element
If(count == 0) Then
Input numbers[count]
Else
lbl: Input digit
If(digit > numbers[count-1]) then
numbers[count] = digit
Else
Output "Number must be greater than the previous number"
Goto lbl
Endif
Endif
count = count + 1
While(count<n)
count = 0
// Input element to count
input search
// Begin searching and counting
Do
if(numbers [count] == search)
countsearch = countsearch+1;
End if
While (count < n)
Output count
Program to illustrate the above
// Written in C++
// Comments are used for explanatory purpose
#include<iostream>
using namespace std;
int main()
{
// Variable declaration
float [] numbers;
int n, count;
float num, searchdigit;
cout<<"Number of array elements: ";
cin>> n;
// Enter array element
for(int I = 0; I<n;I++)
{
if(I == 0)
{
cin>>numbers [0]
}
else
{
lbl: cin>>num;
if(num >= numbers [I])
{
numbers [I] = num;
}
else
{
goto lbl;
}
}
// Search for a particular number
int search;
cin>>searchdigit;
for(int I = 0; I<n; I++)
{
if(numbers[I] == searchdigit
search++
}
}
// Print result
cout<<search;
return 0;
}
