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Dennis_Churaev [7]
3 years ago
15

Question 2 of 5

Mathematics
1 answer:
denpristay [2]3 years ago
3 0
The answer is 5.625 hope it helps
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PLSSS HELP ME thanks :))
krok68 [10]

that's all , all the best

4 0
3 years ago
For an angle θ with the point (−5, −12) on its terminating side, what is the value of cosine?
viva [34]

Answer:

option C. -\frac{5}{13}

Step-by-step explanation:

we have  that

The point (-5,-12) belong to the III quadrant

so

The value of the cosine is negative

Applying the Pythagoras Theorem

Find the value of the hypotenuse

h^{2}=5^{2}+12^{2}\\ h^{2} =25+144\\ h^{2}=169\\h=13\ units

The value of cosine of angle θ is the ratio between the side adjacent to angle θ and the hypotenuse

cos(\theta)=-\frac{5}{13}

8 0
3 years ago
Solve arctan(-sqrt(3))
tatyana61 [14]
We are given with the expression arctan(-sqrt(3)) and asked to evaluate it. In this case, we can use a calculator or the rule of common triangles to answer this question. the value of <span>arctan(-sqrt(3)) is -60. Since negative tan is found in 2nd and 4th quadrant, the angles are 180-60 or 120 degrees and 360-60 or 300 degrees.</span>
6 0
4 years ago
Which ordered pair is the solution to the system of equations?
d1i1m1o1n [39]
\begin{cases}-3x+4y=-20\\y=x-4\end{cases}\\\\\\-3x+4(x-4)=-20\\\\-3x+4x-16=-20\\\\x-16=-20\quad|+16\\\\x-16+16=-20+16\\\\\boxed{x=-4}\\\\\\y=x-4\\\\y=-4-4\\\\\boxed{y=-8}

Answer C.
4 0
3 years ago
Does anyone know how to do this and if so can you please help me and explain how to do it, it’ll be appreciated thank you
dalvyx [7]

Answer:

13) (5x)^{-\frac{5}{4} ⇒ \frac{1}{\sqrt[4]{(5x)^5}}

15) (10n)^{\frac{3}{2} ⇒ \sqrt{(10n)^3}

Step-by-step explanation:

Given expression:

13) (5x)^{-\frac{5}{4}

15) (10n)^{\frac{3}{2}

Write the expressions in radical form.

Solution:

For an expression with exponents as fraction like

(x)^{\frac{m}{n}

the numerator m represents the power it is raised to and the denominator n represents the nth root of the expression.

For an expression with exponents as negative  fraction like

(x)^{-\frac{m}{n}

We take the reciprocal of the term by rule for negative exponents.

So it is written as:

\frac{1}{(x)^{\frac{m}{n}}}

using the above properties we can write the given expressions in radical form.

13) (5x)^{-\frac{5}{4}

⇒ \frac{1}{(5x)^{\frac{5}{4}}}   [Using rule of negative exponents]

⇒ \frac{1}{\sqrt[4]{(5x)^5}}    [writing in radical form]

15) (10n)^{\frac{3}{2}

⇒ \sqrt{(10n)^3}     [Since 2nd root is given as \sqrt{} in radical form]

3 0
3 years ago
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