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bija089 [108]
3 years ago
8

Solve the inequality. |2k + 1| ≥ 5

Mathematics
1 answer:
lara [203]3 years ago
3 0

Answer: k ≥ 2 and k ≤ -3

Step-by-step explanation:

When answering a problem like this, normally, you first isolate the absolute value.  As it is already isolated, the next thing you do is split the equation into 2k + 1 ≥ 5 and 2k + 1 ≥ -5, because the contents of the absolute value could be negative or positive, and simplifying both into k ≥ 2, and k ≤ -3.

Hope it helps <3

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5. Stacy bought 4 trays of eggs at sh.150 per tray.
blagie [28]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
3. What are the intersection points of the line whose equation is y=3x +3 and the
densk [106]

Answer:

Points of intersection of these graphs are (-2, -3) and (0.6, 4.8).

Step-by-step explanation:

Equation of the circle → (x - 2)² + y² = 25 ---------(1)

                                   → (x - 2)² + (y - 0)² = 5²

By comparing this equation with the standard equation of the circle,

(x - a)² + (y - b)²= r²

Here (a, b) is the center and r is the radius of the circle.

Therefore, center of the circle is (2, 0) and radius = 5 units

Second equation is a linear equation → y = 3x + 3 -------(2)

x-intercept of the equation → x = -1

y-intercept of the equation → y = 3

By graphing these equations we can get the point of intersections.

Solving these equations algebraically,

Substitute the value of y from equation (2) in the equation (1),

(x - 2)² + (3x + 3)² = 25

x² - 4x + 4 + 9x² + 18x + 9 = 25

10x² + 14x - 12 = 0

5x² + 7x - 6 = 0

x = \frac{-7\pm \sqrt{7^2-4(5)(-6)}}{2(5)}

x = \frac{-7\pm \sqrt{169}}{10}

x = \frac{-7\pm13}{10}

x = -2, 0.6

From equation (2),

y = -3, 4.8

Therefore, points of intersection of these graphs are (-2, -3) and (0.6, 4.8).

6 0
3 years ago
What are the solutions to<br> (m +11)2 = 64?
mel-nik [20]

Answer:

(21 + 11)2 = 64

So, I don't think teachers do this, but this is my way of doing it

Okay, so first, I divided 64 by 2 :

64 ÷ 2 = 32

Then, I subtracted 11 from 32:

21

Now, to check, just do the problem :

(21 + 11)2 = 64

      32 * 2 = 64

6 0
3 years ago
Read 2 more answers
Can you help me in my math work
Ket [755]

The LCM of 18 and 24 using the prime-factorization method is <u>72</u>.

The LCM of 27, 81, and 54, using the division method is <u>162</u>.

In the first question, we are asked to find the LCM of the given numbers using the prime factorization method.

(i) 18, 24.

Prime factorization gives:

18 = 2*3², and 24 = 2³*3.

The LCM is the product of the highest power of each prime factor.

Thus, LCM = 2³*3² = 8*9 = 72.

Thus, the LCM of 18 and 24 using the prime-factorization method is <u>72</u>.

Doing similarly for other sub-parts, The LCM of:

(ii) 16, 40 is 80.

(iii) 30, 36 is 180.

(iv) 28, 44 is 308.

(v) 20, 32 is 160.

(vi) 20, 135 is 540.

(vii) 45, 75 is 225.

(viii) 36, 84 is 252.

(ix) 12, 18, 24 is 72.

(x) 25, 35, 45 is 1575.

(xi) 9, 15, 21 is 315.

(xii) 25, 50, 75 is 150.

In the second question, we are asked to find the LCM of the given numbers, using the division method.

(i) 27, 81, 54.

The division method gives:

\underline{2|27,81,54}\\\underline{3|27,81,27}\\\underline{3|9,27,9}\\\underline {3|3,9,3}\\\underline{3|1,3,1}\\{1|1,1,1}

The LCM is the product of all the numbers used for division.

LCM = 2*3*3*3*3*1 = 162.

Thus, the LCM of 27, 81, and 54, using the division method is <u>162</u>.

Doing similarly for other sub-parts, The LCM of:

(ii) 18, 45, 63 is 630.

(iii) 35, 55, 100 is 7700.

(iv) 210, 140, 315 is 1260.

(v) 112, 120, 150 is 8400.

(vi) 144, 180, 300 is 3600.

Learn more about LCM at

brainly.com/question/420337

#SPJ1

7 0
2 years ago
If the class creates a histogram of the data in the table, how many students are in the range 12 cm to 13.9 cm?
muminat

Answer:

4 i think

Step-by-step explanation:

5 0
4 years ago
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