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777dan777 [17]
3 years ago
10

A line has a measurable length true or false

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0
False because it just can not
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Determine if the following is true: if sin^2x cos^2x=1, then sinx+cosx=1
SCORPION-xisa [38]

Answer:

true

Step-by-step explanation:

6 0
2 years ago
Brad is putting up a 14 foot diameter circular flower garden in his yard. What is the area of brads garden ?
Lapatulllka [165]

Answer:

The area is about 153.938

Step-by-step explanation:

To find the area of a circle, you have the equation

πr squared

the diameter is 14, so the radius is 7.

pi 7 squared is equal to about 153.938

Please Thank me, Rate, And mark as brainliest if you want!

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4 0
3 years ago
Segment EF is a mid segment of triangle ABC. IF BC = 12 cm, what is the measure of segment EF?
Effectus [21]
The answer is 6 cm. The mid segment is half of BC
8 0
2 years ago
Read 2 more answers
Solve the linear equation. 8x+32=1/5(25x−15)−4x
Kipish [7]

Answer: x= 5

Step-by-step explanation:

8x+32=1/5(25x−15)−4x

8x + 32 = <u>25x -15</u> - 4x   <u><em>- 25x -15/  5</em></u>

                    5

8x + 32 = 5x -3 - 4x

8x + 4x - 5x = -32 - 3

7x =-35

x = 35/7

x= 5

5 0
3 years ago
The national average sat score (for verbal and math) is 1028. if we assume a normal distribution with standard deviation 92, wha
elena55 [62]

Let X be the national sat score. X follows normal distribution with mean μ =1028, standard deviation σ = 92

The 90th percentile score is nothing but the x value for which area below x is 90%.

To find 90th percentile we will find find z score such that probability below z is 0.9

P(Z <z) = 0.9

Using excel function to find z score corresponding to probability 0.9 is

z = NORM.S.INV(0.9) = 1.28

z =1.28

Now convert z score into x value using the formula

x = z *σ + μ

x = 1.28 * 92 + 1028

x = 1145.76

The 90th percentile score value is 1145.76

The probability that randomly selected score exceeds 1200 is

P(X > 1200)

Z score corresponding to x=1200 is

z = \frac{x - mean}{standard deviation}

z = \frac{1200-1028}{92}

z = 1.8695 ~ 1.87

P(Z > 1.87 ) = 1 - P(Z < 1.87)

Using z-score table to find probability z < 1.87

P(Z < 1.87) = 0.9693

P(Z > 1.87) = 1 - 0.9693

P(Z > 1.87) = 0.0307

The probability that a randomly selected score exceeds 1200 is 0.0307

5 0
3 years ago
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