First, simplify the equation given into slope intercept form.
slope intercept form is y = mx + b, where b is the y intercept and m is the slope.
3x - 2y - 5 = 0
I would move the 2y to the other side.
3x - 5 = 2y
Then, since y can't have a coefficient, divide everything by 2;
y = 3/2x - 5/2
So there's your slope intercept form.
Point slope form is:
![y - y_{1} = m( x} - x_{1} )](https://tex.z-dn.net/?f=%20y%20-%20%20y_%7B1%7D%20%3D%20m%28%20x%7D%20-%20%20x_%7B1%7D%20%29)
Where those with a subscript of 1 are part of the same point.
So you already known one point; -8, 8. I'll just do that as the pair with subscript 1. You know the slope as well from the slope intercept form; 3/2.
You can just plug those in.
y - 8 = 3/2 (x + 8)
Now to change this to general form.
First, distribute 3/2 to x and 8.
y - 8 = 3/2x + 12
-3/2x + y = 20
-3/2x + y - 20 = 0
Since there are no fractions, multiply everything by 2.
-3x + 2y - 40 = 0
Answer:
in this diagram their are boxes.
on which 21 are shaded so the fraction is
Step-by-step explanation:
21/100
because their are total 100 boxes and 21 are shaded
hope you like the answer.
Answer:
A counterexample for a conjecture is the statement that disproves a conjecture.
Step-by-step explanation:
To find : What is a counterexample for the conjecture?
Solution :
A conjecture is an educated guess but not yet proven. It is possible that next example shown the conjecture wrong.
A counterexample is an example that disproves or disagree a conjecture.
For example : Prime numbers - 3,7,11,23
Conjecture - All prime numbers are odd
Counterexample - 2
→ 2 is a prime number but not odd, it is an even number.
The force would be 0.04.
This is found by using the formula:
F=mg sinθ
F = 0.01(9.8)sin (22.5)
F ≈ 0.04
It is already given in the question that there are 8 pencils in 1 packet. Based on this information the answer to the question can be easily found out.
Then
Number of pencils in 7 packets = 8 * 7
= 56
So there are 56 pencils in 7 packets. I hope you have got the answer you were looking for. This method would allow you to answer any question of this type.