All categories

2 years ago

Can someone help me out? (Show work on how to solve)

Mathematics

2 answers:

belka [17]2 years ago

8 0

Answer:

dghggjj

Step-by-step explanation:

s gm knfc JC. jz. jz. .xx nkcmxd I nt☺️️

oksian1 [2.3K]2 years ago

3 0

Both of the lines are combined 9 7/10

You might be interested in

Thetime(inhours)requiredtorepairamachineis an exponentially distributed random variable with parameter λ = 1 . What is 2 (a) the

mihalych1998 [28]

Answer:

a) 0.1353

b) 0.3679

Step-by-step explanation:

Let's start by defining the random variable T.

T : ''The time (in hours) required to repair a machine''

T ~ exp (λ)

T ~ exp (1)

The probability density function for the exponential distribution is

(In the equation I replaced λ = L)

$f(x)=Le^{-Lx}$

With L > 0 and x ≥ 0

In this exercise λ = 1 ⇒

$f(x)=e^{-x}$

For a)

$P(T>2)$

$P(T>2)=1-P(T\leq 2)$

$P(T>2)=1-\int\limits^2_0 {e^{-x} } \, dx$

$P(T>2)=1-(-e^{-2}+1)$

$P(T>2)=e^{-2}=0.1353$

For b)

$P(T\geq 10/T>9)$

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur

$P(T\geq 10/T>9)=P(T\geq 1)$

$P(T\geq 1)=1-P(T$

$P(T\geq 1)=1-(-e^{-1}+1)=e^{-1}=0.3679$

4 0

2 years ago

In a regression equation predicting income (measured in $1000s) with education (measured in years), the intercept (a) equals 1.5

Sindrei [870]

Answer:

a. at zero years of education, income equals $1500

Step-by-step explanation:

The equation for income 'I', as a function of years of education 't' is given by:

$i(t) = bt+a$

Where b is the regression coefficient and a is the intercept.

The intercept is the value assumed by the function for t = 0 years of education:

$i(0) = 0*4 +1.5\\i(0) = 1.5$

Since the income function measures income in $1,000s, at zero years of education, income equals $1500

3 0

3 years ago

Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5

Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7 y coordinate=-2

B: x coordinate=1 y coordinate=-2

C: x coordinate=1 y coordinate=-8

D: x coordinate=-7 y coordinate=-8

G: x coordinate=2 y coordinate=5

H: x coordinate=6 y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

The distance between A and B is 8

y coordinate of Vertices AC:

y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that the measure of ABCD is twice GHJK.

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in y coordinate of Vertices GJ is 3.

Points J and K could be located at:

J(2,2)

K(6,2)

3 0

2 years ago

Find the area of an equilateral triangle that has perimeter of 24 m.

mafiozo [28]

we know the perimeter is 24, and is an equilateral triangle, so it has three equal sides, so each side is 24 ÷ 3 = 8.

$\bf \textit{area of an equilateral triangle}\\\\ A=\cfrac{s^2\sqrt{3}}{4}~~ \begin{cases} s=side's\\ \qquad length\\ \cline{1-1} s = 8 \end{cases}\implies A=\cfrac{8^2\sqrt{3}}{4}\\\\\\ A=16\sqrt{3}\implies A\approx 24.71$

6 0

3 years ago

Representing algebraic relationships in tables and graph. Graph each equation y=x+3

KatRina [158]

Answer:

Step-by-step explanation:

To graph this equation, start by plugging in different numbers for X and solve for Y.

For example: When x=0, y=0+3 ⇒ the coordinate is (0,3)

When x=1, y=1+3 ⇒ (1,4)

If you do this enough times, dotting each new coordinate then connecting them in a straight line, you will get your graph.

5 0

2 years ago