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Ivan
3 years ago
6

The graph of a linear function passes through the point (1, -10) and has a slope of -5. Which of these best represents the zero

of the function?
A) 1
B) -1
C) 3
D) -3
Mathematics
2 answers:
blagie [28]3 years ago
4 0

Answer:

Did a picture come with this? If so may I see it. This isnt enough information.

Step-by-step explanation:

dmitriy555 [2]3 years ago
3 0
Is c because I know
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Turn the percentage into a decimal and then multiply. Don’t forget to multiply the percentage with the decimal.
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Derive the equation of the parabola with a focus at (-5,5) and a directix of y = -1
Paladinen [302]

Answer:

D

Step-by-step explanation:

From any point (x, y) on the parabola the focus and directrix are equidistant

Using the distance formula

\sqrt{(x+5)^2+(y-5)^2} = | y + 1 |

Squaring both sides

(x + 5)² + (y - 5)² = (y + 1)^2 , that is

(y + 1)² = (x + 5)² + (y - 5)² ← subtract (y - 5)² from both sides

(y + 1)² - (y - 5)² = (x + 5)² ← expand left side and simplify

y² + 2y + 1 - y² + 10y - 25 = (x + 5)²

12y - 24 = (x + 5)² ← factor left side

12(y - 2) = (x + 5)² ← divide both sides by 12

y - 2 = \frac{1}{12} (x + 5)² ← add 2 to both sides

y = \frac{1}{12} (x + 5)² + 2

or

f(x) = \frac{1}{12} (x + 5)² + 2 → D

7 0
3 years ago
A petting zoo gives out large buckets of healthy popcorn snacks for visitors to feed to the animals. what fraction of the snack
LuckyWell [14K]
Cow- 1/3 = 12/36
goose- 1/12 = 3/36
goat= 2/9 = 8/36

12 + 3 + 8 = 23/36

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Answer:

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Step-by-step explanation:

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8 0
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Suppose that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water
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Answer:

Step-by-step explanation:

Given that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water is pumped into the tank at a rate of 4 gal/min, and when the solution is well stirred, it is then pumped out at the same rate.

Let Q(t) be the quantity of salt at time t.

Q(0) = 70 pounds

Inflow of water = outflow = 4 gal/min

So resulting volume of tank at time t = 400 gallons

Rate of change of salt = inflow - outflow

= 0 - \frac{Q(t)}{400}

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This is a variable separable equation

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A(0) = Q(0) = 70 lbs.

7 0
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