All categories

3 years ago

Ten friends are equally sharing 3 packs of baseball cards. How much of a pack will each friend get?

Mathematics

1 answer:

AfilCa [17]3 years ago

6 0

Each friend will get 3 and 1/3 of a pack of baseball cards

You might be interested in

Write the following fractions greater than 1as a sum of two products

cestrela7 [59]

What are the following fractions

7 0

3 years ago

PLS ANSWER THE FOLOWWING QUESTION

sashaice [31]

Answer:

Lines p and q are parrallel.

Step-by-step explanation:

Lines are 180 degrees. We can use that to find out the other angles.

180 - 140 = 40

180 - 40 = 140

6 0

3 years ago

R=8.4mi find the Circumference to the nearest 10th with pi being 3.14

alukav5142 [94]

Your answer should be 52.8

4 0

4 years ago

Please answer this fast Will mark brainiest

OLEGan [10]

Answer:

20 <h<30

Step-by-step explanation:

There are 30 plants so the medians is 30/2 = 15, between the 15 and 16 items

15 and 16th items are in the range 20 to 30, so the median is between 20 to 30

20 <h<30

3 0

3 years ago

Read 2 more answers

What’s the differential equation of

worty [1.4K]

Answer:

$y=\frac{1}{x^{2}-6x+13 }$

Step-by-step explanation:

We have given,

$\frac{dy}{dx}=y^{2}(6-2x)$

and initial condition $x=3,\ y=\frac{1}{4}$

Now,

$\frac{dy}{dx}=y^{2}(6-2x)$

Rearranging the variables, we get

$\frac{dy}{y^{2} }=(6-2x).dx$

Applying integration both sides, we get

$\int\ {\frac{dy}{y^{2} } } \,=\int\ {(6-2x).} \, dx$

⇒ $\frac{-1}{y} =6x-\frac{2x^{2} }{2}$

⇒ $\frac{-1}{y}=6x-x^{2} +C$

Putting the initial condition (i.e., $x=3,\ y=\frac{1}{4}$ ), we get

⇒ $-4=6\times3-(3)^{2}+C$

⇒ $-4=18-9+C$

∴ $C=-13$

We have, $\frac{-1}{y}=6x-x^{2} +C$

now putting the value of $C$ in above equation, we get

⇒ $\frac{-1}{y}=6x-x^{2} -13$

⇒ $\frac{1}{y}=-6x+x^{2} +13$

$y=\frac{1}{x^{2}-6x+13 }$

5 0

3 years ago