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tatyana61 [14]
3 years ago
15

What is equivalent to 1 over 9

Mathematics
2 answers:
krek1111 [17]3 years ago
4 0

Answer:

Step-by-step explanation:

2/18

3/27

4/36

Eva8 [605]3 years ago
4 0

Answer:

.1111111111

Step-by-step explanation:

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Graph the line with: a slope of -5 and y intercept of 4. PLEASE HELP
worty [1.4K]

The y intercept of 4 means the graph crosses the vertical y axis at 4. More specifically this location is (0,4)

Start at (0,4) and move down 5 units and then move to the right 1 unit. You should arrive at (1,-1). The movement rule of "down 5, over to the right 1" is taken exactly from the slope of -5 = -5/1.

After plotting the two points (0,4) and (1,-1), draw a straight line through them both. Extend this line as far as you can in either direction. The graph is now completed.

<h3>In summary, this line goes through (0,4) and (1,-1)</h3>

Side note: The equation of this line is y = -5x+4. It is in slope intercept form.

5 0
3 years ago
How many times greater is one pound than one ounce?
Vesna [10]
<span>There are 16 ounces in 1 pound therefore your answer is 16 times greater than an ounce.</span>
3 0
4 years ago
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For what value of p would the statement 5p = 30 be true?<br>​
shtirl [24]

Answer:

6

Step-by-step explanation:

divide both sides of the equals by 5 to get p on its own

5p divided by 5 = p

30 divided by 5 = 6

6 0
3 years ago
In d Mohit deposited 2 12000 be depos would ( money 900. The interest B 800 o O 1800​
jeka57 [31]

I need the answer too lol, does anyone knows it ?

5 0
2 years ago
A company deposits $5,000 into an account that earns interest. The rate at which the value changes is given by dA/dt=0.0225A, wh
xxMikexx [17]

Answer:

  $6261.61

Step-by-step explanation:

The solution to the differential equation is the exponential function ...

  A(t) = 5000e^(0.0225t)

We want the account value after 10 years:

  A(10) = 5000e^(0.225) = 6261.61

The value of the account after 10 years will be $6,261.61.

_____

The rate of change equation basically tells you that interest is compounded continuously. After working interest problems for a while you know the formula for that is the exponential formula A = A0·e^(rt).

Or, you can solve the differential equation using separation of variables:

  dA/A = 0.0225dt

  ln(A) = 0.0225t +C . . . . integrate

  A(t) = A0·e^(0.0225t) = 5000·e^(0.0225t) . . . . solution for A(0) = 5000

7 0
3 years ago
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