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2 years ago

How is the rangeof a set of data different from a IQR

2 answers:

4 0

Suppose you're given a set of data. Arrange it in ascending order, from smallest to largest.

The "range" of this data can be thought of as "smallest to largest." Alternatively, you could subtract the smallest value from the largest and call that the "range" of the data set. That's it.

On the other hand, finding the IQR of a data set requires more work. Again, arrange the data in ascending order. Now identify the median as well as the first and third quartiles. Subtract the first quartile from the third quartile. The result is your IQR.

The tradeoff in doing more work to find the IQR is that the results tell us more about how the data set is distributed.

Lady_Fox [76]2 years ago

3 0

It is defined as the difference between the largest and smallest values in the middle 50% of a set of data. To compute an interquartile range using this definition, first remove observations from the lower quartile. Then, remove observations from the upper quartile.

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Barry's employer pays $1,945 in health insurance and $234 in life insurance per year. He also gets $4,213 in paid time off per y

My name is Ann [436]

Step-by-step explanation:

the job benefits is everything he gets in addition to the regular salary.

that is here

$1945 health insurance

$ 234 life insurance

$4213 paid time off

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$6392 job benefits per year

4 0

3 years ago

The Diaz family bought 7 bags of cookies. Each bag had 14 cookies. They have since eaten 29 of the cookies. How many cookies do

saveliy_v [14]

Answer:

They have 69 cookies left.

Step-by-step explanation:

7 x 14 = 98

98 - 29 = 69

6 0

3 years ago

F-7/g = h for f solve for f

gregori [183]

(f - 7)/g = h
f - 7 = gh
f = gh + 7

5 0

3 years ago

What is the answer and why is it that answer

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

73+107 = 180. When the smaller of the two angles is 73 all of the smaller angles are also going to be 73 and since the angles MTS and STN are bigger angles they both have to be 107

5 0

3 years ago

I need help with this. Thanks I need to find the degree

scoundrel [369]

Answer:

119.05°

Step-by-step explanation:

In general, the angle is given by ...

θ = arctan(y/x)

Here, that becomes ...

θ = arctan(9/-5) ≈ 119.05°

_____

Comment on using a calculator

If you use the ATAN2( ) function of a graphing calculator or spreadsheet, it will give you the angle in the proper quadrant. If you use the arctangent function (tan⁻¹) of a typical scientific calculator, it will give you a 4th-quadrant angle when the ratio is negative. You must recognize that the desired 2nd-quadrant angle is 180° more than that.

It may help you to consider looking at the "reference angle." In this geometry, it is the angle between the vector v and the -x axis. The coordinates tell you the lengths of the sides of the triangle vector v forms with the -x axis and a vertical line from that axis to the tip of the vector. Then the trig ratio you're interested in is ...

Tan = Opposite/Adjacent = |y|/|x|

This is the tangent of the reference angle, which will be ...

θ = arctan(|y| / |x|) = arctan(9/5) ≈ 60.95°

You can see from your diagram that the angle CCW from the +x axis will be the supplement of this value, 180° -60.95° = 119.05°.

3 0

3 years ago