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MrMuchimi
3 years ago
9

How is the rangeof a set of data different from a IQR

Mathematics
2 answers:
Elena L [17]3 years ago
4 0
Suppose you're given a set of data.  Arrange it in ascending order, from smallest to largest.  

The "range" of this data can be thought of as "smallest to largest."  Alternatively, you could subtract the smallest value from the largest and call that the "range" of the data set.  That's it.

On the other hand, finding the IQR of a data set requires more work.  Again, arrange the data in ascending order.  Now identify the median as well as the first and third quartiles.  Subtract the first quartile from the third quartile.  The result is your IQR.

The tradeoff in doing more work to find the IQR is that the results tell us more about how the data set is distributed.
Lady_Fox [76]3 years ago
3 0
It is defined as the difference between the largest and smallest values in the middle 50% of a set of data<span>. To compute an </span>interquartile range<span> using this definition, first remove observations from the lower quartile. Then, remove observations from the upper quartile.</span>
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Use the following problem to answer questions 8 and 9. A television manufacturer has three locations where it is finally assembl
Nonamiya [84]

Answer:

The probability of finding a non-defective television is 0.9815.

Step-by-step explanation:

We are given that a television manufacturer has three locations where it is finally assembled. Plants A, B, and C supply 65%, 15%, and 20% respectively of the televisions used by the manufacture.

Quality control has determined that 1.5% produced by Plant A are defective, while plants B and C have 2.5% defective products.

Let Probability that Plant A supply televisions = P(A) = 0.65

Probability that Plant B supply televisions = P(B) = 0.15

Probability that Plant C supply televisions = P(C) = 0.20

<em>Also, let D = event that television is defective</em>

Probability that television is defective given that it is supplied by Plant A = P(D/A) = 0.015

Probability that television is defective given that it is supplied by Plant B = P(D/B) = 0.025

Probability that television is defective given that it is supplied by Plant C = P(D/C) = 0.025

<u>Now, to find the probability of finding a non-defective television firstly we will find the probability of a defective television.</u>

<em>Probability of a defective television is given by;</em>

   =  P(A) \times P(D/A) + P(B) \times P(D/B) + P(C) \times P(D/C)  

   =  0.65 \times 0.015 + 0.15 \times 0.025 + 0.20 \times 0.025  

   =  0.00975 + 0.00375 + 0.005

   =  0.0185

Now, <em><u>probability of finding a non-defective television</u></em> = 1 - Pro<em>bability of a defective television</em>

Probability of finding a non-defective television = 1 - 0.0185

                                                                                   = 0.9815

<em>Therefore, the probability of finding a non-defective television is 98.15%.</em>

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3 years ago
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Brilliant_brown [7]

Answer:

y=-14acfr+5x

Step-by-step explanation:

hope it helps

6 0
3 years ago
Brandi sells insurance plans that cost $1,500 each. She makes a 7.5% commission on each plan that she sells. Her goal is to make
scoundrel [369]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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How do i Evaluate this expression?​
timofeeve [1]

\text{Hey there!}

\bf{9.83+8.2(7.01)}

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\text{PEMDAS simply means}\downarrow

\text{Parentheses }

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\text{Multiplication}

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\text{Addition}

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\text{9.83 + 8.2(7.01)}

\text{8.2(7.01)=57.482}

\text{9.83 + 57.482 = 67.312}

\boxed{\boxed{\text{Thus your answer is most likely: \bf{67.312}}}}\checkmark

\text{Good luck on your assignment and enjoy your day!}

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3 0
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forsale [732]

Answer:

1/3

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for every 1 part of water there is 3 parts juice so if there's only 1 part juice it would be a 1/3

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