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A man is five times as old as his son. Four years ago the man was thirteen times as old as his son.

skad [1K]

Answer:

Age of son = 6 years

Age of man = 5×6 = 30 years

Step-by-step explanation:

GIVEN :-

A man is 5 times as old as his son. (In Present)
4 years ago , the man was 13 times as old as his son

TO FIND :-

The present ages of the man & his son.

SOLUTION :-

Let the present age of son be 'x'.

⇒ Present age of man = 5x

4 years ago ,

Age of son = (Present age of son) - 4 = x - 4

Age of man = (Present age of man) - 4 = 5x - 4

The man was thirteen times as old as his son. So,

$=> 5x - 4 = 13(x - 4)$

Now , solve the equation.

Open the brackets in R.H.S.

$=> 5x - 4 = 13x - 52$

Take 5x to R.H.S. and -52 to L.H.S. Also , take care of their signs because they are getting displaced from L.H.S. to R.H.S. or vice-versa.

$=> 13x - 5x = 52 - 4$

$=> 8x = 48$

Divide both the sides by 8

$=> \frac{8x}{8} = \frac{48}{8}$

$=> x = 6$

CONCLUSION :-

Age of son = 6 years

Age of man = 5×6 = 30 years

8 0

2 years ago

Help me with this ASAP!!!

joja [24]

Answer:

5

Step-by-step explanation:

6 0

3 years ago

What is the minimum value of C = 7x + 8y, given the constraints: 2x + y ≥ 8, x + y ≥ 6, x ≥ 0, y ≥ 0. A. 32 B. 42 C. 46 D. 64

marshall27 [118]

Answer: The minimum value of C is 46.

Step-by-step explanation:

Since, Here, We have to find out Min C = 7x+8y

Given the constraints are $2x+y\geq 8$ -------(1)

$x+y \geq 6$ ------------- (2)

$x \geq 0$ , $y \geq 0$ -------- (3)

Since, For equation 1) x-intercept, (4, 0) and y-intercept (0,8)

And, $2\times 0+0\geq 8$ ⇒ $0\geq 8$ ( false)

Therefore the area of line 1) does not contain the origin.

For equation 2) x-intercept, (6, 0) and y-intercept (0,6)

And, $0+0\geq 6$ ⇒ $0\geq 6$ ( false)

Therefore the area of line 2) does not contain the origin.

Thus after plotting the constraints 1) 2) and 3) we get Open Shaded feasible region AEB ( Shown in below graph)

At A≡(0,8) , C= 64

At E≡(2,4), C= 46

At B≡(6,0), C= 42

Thus at B, C is minimum, And its minimum value = 42

5 0

3 years ago

Read 2 more answers

Concept maps work because they _______.

AnnZ [28]

Showing the relationships among concepts.

7 0

3 years ago

Read 2 more answers

Help me please with this Simplify. 5a-12a

Oduvanchick [21]

It helps to imagine the variable a sort of as a unit. Like with 5 minus 12 lemons, it has no bearings on the addition/subtraction here.

Factor out a and subtract.

$5a-12a \\ (5-12)a \\ \boxed{-7a}$

4 0

3 years ago