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andrew-mc [135]
3 years ago
9

Ling drove at a speed of 45 miles per hour for 225 miles. How many hours did she drive?

Mathematics
2 answers:
vovangra [49]3 years ago
7 0
The is five hours because you divide 225 miles by 45 miles
vladimir2022 [97]3 years ago
4 0

The answer is 5 hours so that person was correct

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One fourth of the 120 students took wood shop. How many students did not take wood shop?
yawa3891 [41]

Answer:

90 students.

Step-by-step explanation:

Given 1/4 of the 120 students took woodshop, just take the 3/4 that didn't take it:

\frac{3}{4}(120)

Find common factors between 4 and 120 to simplify, so 4.

\frac{3}{1} (30)

Now multiple across to get 90.

5 0
3 years ago
there are five people in a room each person shakes the hand of every person exacally once how many handshakes or exchanged
nalin [4]
25  because there's 5 people so you take 5 times 5
5 0
4 years ago
An airplane can seat up to 175 passengers. The airline has already sold 87 tickets for a flight on the airplane. Which
spayn [35]

The inequality is solved, and then, the graph is given at the end of this question.

------------------

  • 87 tickets have already been sold.
  • x can still be sold.
  • In total, the number of tickets sold is 87 + x.
  • The airplane can seat 175 passengers, thus, the total can be at most 175, that is:

87 + x \leq 175

x \leq 175 - 87

x \leq 88

  • The solution is given on a graph at the end of this answer.

A similar problem is given at brainly.com/question/24132092

7 0
2 years ago
Solve the missing tables part 2.
Nimfa-mama [501]
Hopefully this helps

3 0
3 years ago
The​ life, in​ years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o
Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

\bf P(X

So, the probability that a switch fails in the first year is

\bf P(X

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and  

\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}

where  

\bf \binom{100}{k} equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999

3 0
3 years ago
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