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harkovskaia [24]
3 years ago
11

2x+5+2x+3x=6x+7 Help ASAP plzzzzz

Mathematics
2 answers:
BartSMP [9]3 years ago
8 0

Answer: X=2

2x plus 2x plus 3x equals 7x and then you add the +5 which means you now have 7x+5=6x+7 which you then solve from there by subtracting the 6x from the left side. You then get x+5=7 meaning x=2.

Blizzard [7]3 years ago
7 0

Answer:25x

Step-by-step explanation:

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To save at least $15,000 in 5 years, which monthly deposit is the minimum amount an eighth grader and his family should plan to
sergejj [24]

Answer:

C $250

Step-by-step explanation:

based on the question we can get the equation

where m = money, the years are converted to months

15000 = 60m

divide by 60 to each side

m= 250

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Work out the volume of this hemisphere with diameter 9.6 cm
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John checked his watch and said that it is Thursday, 7 am. What will the day and time be 2006 hours later??? Plzzz I will give y
Wewaii [24]

Answer:

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7 0
3 years ago
When the expression $-2x^2-20x-53$ is written in the form $a(x+d)^2+e$, where $a$, $d$, and $e$ are constants, then what is the
Sladkaya [172]
We start with 2 x^{2} -20x-53 and wish to write it as a(x+d) ^{2} +e

First, pull 2 out from the first two terms: 2( x^{2} -10x)-53

Let’s look at what is in parenthesis. In the final form this needs to be a perfect square. Right now we have x^{2} -10x and we can obtain -10x by adding -5x and -5x. That is, we can build the following perfect square: x^{2} -10x+25=(x-5) ^{2}

The “problem” with what we just did is that we added to what was given. Let’s put the expression together. We have 2( x-5) ^{2}-53 and when we multiply that out it does not give us what we started with. It gives us 2 x^{2} -20x+50-53=2 x^{2} -20x-3

So you see our expression is not right. It should have a -53 but instead has a -3. So to correct it we need to subtract another 50.

We do this as follows: 2(x-5) ^{2}-53-50 which gives us the final expression we seek:

2(x-5) ^{2}-103

If you multiply this out you will get the exact expression we were given. This means that:
a = 2
d = -5
e =  -103

We are asked for the sum of a, d and e which is 2 + (-5) + (-103) = -106


7 0
3 years ago
Let f(x)=x^3-3x^2+3.
rusak2 [61]

Answer:

a) Domain: all real values of x

Range: all real values of y

b) Relative maxima: (0,3)

Relative minima: (2,-1)

c) yes, (1,1)

d) x < 0, x > 2

Step-by-step explanation:

a) Domain: all real values of x

Range: all real values of y

b) dy/dx = 3x² - 6x = 0

3x(x - 2) = 0

x = 0, y = 0³ - 3(0)² + 3 = 3

x = 2, y = 2³ - 3(2)² + 3 = -1

d²y/dx² = 6x - 6

x = 0, d²y/dx² = -6 < 0 (max)

x = 2, d²y/dx² = 6 > 0 (min)

c) d²y/dx² = 0 at points of infection

6x - 6 = 0

x = 1

y = 1³ - 3(1)² + 3 = 1

dy/dx at x = 0.9: 3(0.9)² - 6-(0.9)

= -0.298

dy/dx at x = 1.1: 3(1.1²) - 6(1.1)

= -0.297

Decreasing on both sides, therefore (1,1) is a point of inflection

d) increasing when dy/dx > 0

3x² - 6x > 0

Roots: x = 0, 2

x < 0, x > 2

5 0
3 years ago
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