11 school days are left.
In the attached picture of a calendar, I marked the days the person has left. There are 11.
What is the interval notation for the pic above?!
2 answers:
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Given that , we have
, so that
Take the derivative and find the critical points of :
Take the second derivative and evaluate it at the critical point:
Since is positive for all
, the critical point is a minimum.
At the critical point, we get the minimum value .
G(x) = 3x² - 5x + 7
g(-x) = -(3x² - 5x + 7)
g(-x) = -3x² + 5x - 7
This equation cannot be solved because of a few reasons,
1. This equation didn't show that it equals to 0.
2. Even if it equals to zero, square root of a negative number cannot be solved.
(I will show you what I mean)
-3x² + 5x - 7
is the same as
3x² - 5x + 7
by shifting the equation,
for example,
1 - 3 = -2
shifting other side
2 = -1 + 3
using 3x² - 5x + 7 to solve,
a = 3
b = -5
c = 7
∴This equation cannot be solved.
g(-x) = -(3x² - 5x + 7)
g(-x) = -3x² + 5x - 7
This equation cannot be solved because of a few reasons,
1. This equation didn't show that it equals to 0.
2. Even if it equals to zero, square root of a negative number cannot be solved.
(I will show you what I mean)
-3x² + 5x - 7
is the same as
3x² - 5x + 7
by shifting the equation,
for example,
1 - 3 = -2
shifting other side
2 = -1 + 3
using 3x² - 5x + 7 to solve,
a = 3
b = -5
c = 7
∴This equation cannot be solved.