Question

A cube with a mass of m = 560 kg is totally immersed in a liquid of density p = 0.96 g/cm^3. The cube has a edge length of L=1.8m and is held at a deth of d=1.3 m from the top of the cube to the surface of the liquid.

Answer 1

Answer:

The question has some missing details. here are the missing part of the question ;

a) Enter an expression for the difference between the fluid pressure acting on the bottom surface of the cube and that acting on the top surface, in terms of the defined quantities and the acceleration due to gravity, g.

b) Calculate the difference, in pascals, between the fluid pressure acting on the bottom surface of the cube and that acting on the top surface.

c) Enter an expression for the difference between the magnitude of the force the liquid exerts on the bottom surface of the cube and the magnitude of the force it exerts on the top surface, in terms of the defined quantities and the acceleration due to gravity, g. This is the magnitude of the net vertical force the liquid exerts on the cube. That force points up and is called the buoyant force, denoted Fb.

d) Calculate the magnitude of the buoyant force, in newtons, that the liquid exerts on the cube

Explanation:

The detailed steps and appropriate substitution is as shown in the attachment.