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Rzqust [24]
3 years ago
13

If a solar photovoltaic panel produces 1,000 watts of electrical energy and is active for 12 hours each day, how many kwh of ele

ctricity will be produced in a week?
Physics
1 answer:
Masteriza [31]3 years ago
7 0

Answer;

=84 kwh

Explanation;

Electrical energy = 1000 watts

1000 watt = 1 kilo watt

1 week = 7 days

Number of hours = 7 × 12× = 84 hours

Consumption

= 1 kw × 84 hours

= 84 kwh

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If the Sun subtends a solid angle Ω on the sky, and the flux from the Sun just above the Earth’s atmosphere, integrated over all
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Answer:

A)Ω = 7.8 × 10^−5 steradians.

B) TE = 5800K

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A) First of all, if we assume that the Sun emits isotropically at a luminosity (L⊙) , the flux at a given distance R from the sun would be f(d) = L⊙/ (4πd^2)

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Now if we think of this relationship of the flux and the earth as a conical pattern, we'll deduce that the solid angle subtended by the sun at Earth’s surface to be;

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F⊙ = {f(d⊙ )π} /Ω

Now let's express The radius of the sun (R) in terms of its angular diameter (2α) and this gives;

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Now combining this with the equation for Ω earlier, we get;

Ω ≈ πα^2

So, = π((0.57/2π) /180)^2 = 7.8 × 10^−5 steradians.

B) from Stefan-Boltzmann Law,

F⊙ = σ(TE)^4

From the beginning, we know that;

F⊙ = {f(d⊙ )π} /Ω

And so replacing that in the stephan boltzmann law, we get ;

{f(d⊙ )π} /Ωσ = (TE)^4

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In stephan boltzmann law, σ = 5.66961 × 10^(−8)

And so, TE is approximately 5800K.

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Fλ(λ1) = πBλ(T)

Now, if we combine this with the expression of F⊙ gotten earlier, well get the relation;

fλ(λ1) = (π ^2 ) /ΩBλ(T)

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