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sergey [27]
2 years ago
5

Fortnite is Soooooooooooooo trash apex legends is better lol

Physics
2 answers:
MaRussiya [10]2 years ago
7 0

You are right :P

Apex Legends is good!

pshichka [43]2 years ago
4 0
I hate apex but love it at the same time
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A dragster runs the quarter mile in 8.96 s. What is the car's velocity (in ft/s) at the finish line?
lara [203]
The first thing you should know to answer this question is the following conversion:
 1mi = 5280feet
 We have then that the speed is:
 v = ((1/4) * (5280)) / (8.96)
 v = 147.32 feet / s
 Answer:
 the car's velocity (in ft / s) at the finish line is 147.32 feet / s
7 0
3 years ago
What is the wavelength of an earthquake wave if it has a speed of 12 km/s and a frequency of 15 Hz
professor190 [17]
First change km/ s into m/s, then use the formula
Lambda = velocity/ frequency
3 0
3 years ago
describe what happens to the arrangement of water molecules as ice is\to liquid to vapor be sure to explain the temperature chan
alex41 [277]
Water freezes at the freezing point to ice then melts to the melting turning it to liquid and vapor causing gas in precipitation
8 0
3 years ago
A)
Ksenya-84 [330]

Answer:

50N

Explanation:

is the opposing fotce

4 0
3 years ago
How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 3.33××10âˆ
AlekseyPX

Answer:

There are 756.25 electrons present on each sphere.

Explanation:

Given that,

The force of repression between electrons, F=3.33\times 10^{-21}\ N

Let the distance between charges, d = 0.2 m

The electric force of repulsion between the electrons is given by :

F=k\dfrac{q^2}{r^2}

q=\sqrt{\dfrac{Fr^2}{k}}

q=\sqrt{\dfrac{3.33\times 10^{-21}\times (0.2)^2}{9\times 10^9}}

q=1.21\times 10^{-16}\ C

Let n are the number of excess electrons present on each sphere. It can be calculated using quantization of charges. It is given by :

q = ne

n=\dfrac{q}{e}

n=\dfrac{1.21\times 10^{-16}}{1.6\times 10^{-19}}

n = 756.25 electrons

So, there are 756.25 electrons present on each sphere. Hence, this is the required solution.

8 0
3 years ago
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