Simplify please help me
2 answers:
You might be interested in
The derivative, f'(x) = 6x^2+1, is never negative, so f(x) is monotonic, hence invertible.
f'(-2) = 6(-2)²+1 = 25
If point (-2, -26) is on the graph of function f(x), and the slope is 25 there, then (-26, -2) is on the graph of f⁻¹(x), and the slope is 1/25 there. The equation of the tangent line throught that point can be written in point-slope form as
... y +2 = (1/25)(x +26)
Answer:
Option A
x=6 , y=9
Step-by-step explanation:
As we can see in the figure that point T is the mid point of rectangle and there are two diagonals QS and PR
So in basic geometry we know that the length of the diagonal from the mid point i.e. Taking the diagonal QS the length of QT and TS would be equal because they are same diagonal which is cut into two parts by point T
Similarly the Length of RT and the length of TP would be same
From all this we deduct that
3x = 2y ..................(i)
and
y + 3 = 2x ................(ii)
From equation (i)
3x = 2y
Dividing both sides by 3 the equation becomes
x= ....................(iii)
Putting this value in equation (ii)
y + 3 = 2()
y+3 =
multiplying both sides by 3
3(y+3)=
the equation becomes
3y+9=4y
subtracting 3y from both sides
3y-3y+9=4y-3y
y=9
Putting the value of y in equation (iii)
x=
solving it
x=
x=6
so x=6 and y=9 is answer which is option A