The student did not make the opening of each arc drawn from S and T greater than half the length of the line ST. When drawing a perpendicular bisector, the arcs should go past the center of the line segment.
Answer:
x = - 4
Step-by-step explanation:
Given
3 - 2 |0.5x + 1.5 | = 2 ( subtract 3 from both sides )
- 2 |0.5x + 1.5 | = - 1 ( divide both sides by - 2 )
|0.5x + 1.5 | = 0.5
The absolute value function always gives a positive value, however, the expression inside can be positive or negative, thus
0.5x + 1.5 = 0.5 ( subtract 1.5 from both sides )
0.5x = - 1 ( divide both sides by 0.5 )
x = - 2 ← solution Manuela obtained
OR
-(0.5x + 1.5) = 0.5 ← distribute parenthesis on left side by - 1
- 0.5x - 1.5 = 0.5 ( add 1.5 to both sides )
- 0.5x = 2 ( divide both sides by - 0.5 )
x = - 4 ← other solution to the equation
D(t)=-16t²+32t+88
a] Maximum height
At maximum height d'(t)=0
from d(t);
d'(t)=-32t+32=0
thus
t=1
hence the maximum height will be:
d(t)=-16t²+32t+88
d(1)=-16(1)^2+32(1)+88
d(1)=104 ft
2] <span> how many seconds does it take to reach the ground after first being thrown upward?
Here we solve for t intercept
</span>when d(t)=0
<span>thus</span>
0=-16t²+32t+88
<span>solving for t, we get:
t=1-</span>√13/2
or
<span>t=1+</span>√13/2
<span>
t=-1.55 or t=3.55 sec
Thus the answer is t=3.55 sec
</span>
Answer:
Step-by-step explanation:
This looked very difficult UNTIL I looked at the pyramid as ONE HALF of a larger pyramid! Image a mirror image of the pyramid creating a pyramid that is 12 cm of the front and back side and 6 cm on the left and right edge.
IT IS NO LONGER A SQUARE PYAMID so you need the volume for a rectanglar pyramid
The volume of a square pyramide is .....
V = side² × (height / 3)
The volume of a rectangular pyramide is .....
V = base area × (height / 3)
= length × width × (height / 3)
= 12 × 6 × 10 / 3 cm³ BUT REMEMBER we want only HALF of the
= [12 × 3 × 10] divide by 2 cm³ Rectangular pyamid
Volume of the image shown in the diagram is ....
= 360 / 2 cm³
= 180 cm³ <----------------- Final Answer
