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Alex73 [517]
3 years ago
5

Manuela solved the equation 3−2|0.5x+1.5|=2 for one solution. Her work is shown below. 3−2|0.5x+1.5|=2 −2|0.5x+1.5|=−1 |0.5x+1.5

|=0.5 0.5x+1.5=0.5 0.5x=−1 x=−2 What is the other solution to the equation? x=−6 x=−4 x=2 x=4
Mathematics
2 answers:
adoni [48]3 years ago
5 0

Answer:

x = - 4

Step-by-step explanation:

Given

3 - 2 |0.5x + 1.5 | = 2 ( subtract 3 from both sides )

- 2 |0.5x + 1.5 | = - 1 ( divide both sides by - 2 )

|0.5x + 1.5 | = 0.5

The absolute value function always gives a positive value, however, the expression inside can be positive or negative, thus

0.5x + 1.5 = 0.5 ( subtract 1.5 from both sides )

0.5x = - 1 ( divide both sides by 0.5 )

x = - 2 ← solution Manuela obtained

OR

-(0.5x + 1.5) = 0.5 ← distribute parenthesis on left side by - 1

- 0.5x - 1.5 = 0.5 ( add 1.5 to both sides )

- 0.5x = 2 ( divide both sides by - 0.5 )

x = - 4 ← other solution to the equation

maria [59]3 years ago
4 0

Answer:

b on edg

Step-by-step explanation:

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Answer:

D. 16 km

Step-by-step explanation:

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6 0
2 years ago
What is the largest x where f(x) is discontinuous<br> show work
natulia [17]

Answer:

x = 3

Step-by-step explanation:

reverse foil the denominator and find the largest solution.

x-3(x+1)

3 is the largest solution

6 0
2 years ago
Find center,foci, and vertices of ellipse (x+3)^2/21+(y-5)^2/25=1
sasho [114]
I don't know if we can find the foci of this ellipse, but we can find the centre and the vertices. First of all, let us state the standard equation of an ellipse. 

(If there is a way to solve for the foci of this ellipse, please let me know! I am learning this stuff currently.) 

\frac{(x-x_{1})^2}{a^2}+ \frac{(y-y_{1})^2}{b^2}=1

Where (x_{1},y_{1}) is the centre of the ellipse. Just by looking at your equation right away, we can tell that the centre of the ellipse is: 

(-3,5)

Now to find the vertices, we must first remember that the vertices of an ellipse are on the major axis. 

The major axis in this case is that of the y-axis. In other words, 

b^2>a^2 

So we know that b=5 from your equation given. The vertices are 5 away from the centre, so we find that the vertices of your ellipse are: 

(-3,10)
 & (-3,0)

I really hope this helped you! (Partially because I spent a lot of time on this lol) 

Sincerely,

~Cam943, Junior Moderator
6 0
3 years ago
NEED HELP ASAP PLEASE AND THANK YOU<br> ALEGRA 1
sammy [17]
16 and 157
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3 years ago
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3 years ago
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