3 years ago

Where n represents the position in the sequence

1 answer:

8 0

If you look at the position they all go up one and the value of terms all go up by 3 so 4+1=5 so 5 goes where no is and and 11+3=14

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Black_prince [1.1K]

Answer: FALSE.

Step-by-step explanation:

Given the following equation provided in the exercise:

$x-13=x+1$

You need to solve for the variable "x".

In order to solve for "x" you can folllow the steps shown below:

1. You must apply the Addition property of equality and add 13 to both sides of the equation. Then:

$x-13+(13)=x+1+(13)\\\\x=x+14$

2. Finally you need to apply the Subtraction property of equality and subtract "x" from both sides of the equation. So you get:

$x-(x)=x+14-(x)\\\\0=14\ (FALSE)$

Therefore, as you can observe, the given equation has no solutions.

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