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melamori03 [73]
3 years ago
9

For this item select in the choice matrix by clicking the appropriate boxes in each row

Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0

Answer:

(a):\ y = \frac{x + 3}{7} --- Function

(b): Not a function

(c): A function

Step-by-step explanation:

Given

See attachment

Required

Determine if each relation is a relation or not

A function is represented as: \{(x_1,y_1),(x_2,y_2),(x_3,y_3)...(x_n,y_n)\}

Where

x = domain and y = range

For a relation to be a function:

No x value (in other words, the domain) must be repeated

(a):\ y = \frac{x + 3}{7}

The above relation is a function. This is so because every unique value of x have a unique value of y.

In other words:

No two domains exist for a range

<em>Conclusively, it is a one-to-one function</em>

(b):

\begin{array}{ccccc}x & {-2} & {-2} & {1} & {3} \ \\ y & {-5} & {-1} & {3} & {7} \ \ \end{array}

In the above table, we have:

(x_1,y_1) = (-2,5) and (x_2,y_2) = (-2,-1)

The domain (-2) points to range (5 and -1).

Based on the condition that no two domain should point to the same range, we can conclude that this is not a function.

(c):

\begin{array}{ccccc}x & {-3} & {-1} & {1} & {3} \ \\ y & {-4} & {-4} & {2} & {2} \ \ \end{array}

In the above table, we have the domain to be:

x = \{-3,-1,1,3\}

We can see that no x value is repeated.

<em>Hence, this is a function.</em>

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