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svetlana [45]
2 years ago
10

Simplification -4a+b+3c+3a-3b+c​

Mathematics
1 answer:
damaskus [11]2 years ago
7 0

Answer:

-a+-2b+4c

Step-by-step explanation:

Combine like terms

-4a+ 3a= -a

b+ -3b= -2b

3c+ c= 4c

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3(1)+2(_)=6<br><br> plz help on filling in the blank
TEA [102]

Answer:

x = 3/2

Step-by-step explanation:

Let's solve your equation step-by-step.

(3)(1)+2x=6

Step 1: Simplify both sides of the equation.

(3)(1)+2x=6

3+2x=6

2x+3=6

Step 2: Subtract 3 from both sides.

2x+3−3=6−3

2x=3

Step 3: Divide both sides by 2.

2x/2  3/2

x = 3/2

Hope this helps :)

7 0
3 years ago
Please help! Find the value of c in the isosceles trapezoid.
nadezda [96]

Answer:

u lookn hot tonight baby

Step-by-step explanation:

7 0
2 years ago
7x[(9+4)-(12-7)] please help me:(
lara [203]

Answer:

56

Step-by-step explanation:

7((9+4)-(12-7))

7(13-5)

7×8

3 0
3 years ago
Read 2 more answers
Manuel bought 2kg of jelly beans and 2kg of gummy worms for a total of $26. Danny bought 2kg of jelly beans and 3kg of gummy wor
charle [14.2K]

Answer:

Jelly beans: $6 for 1 kg

Gummy worms: $7 for 1 kg

Step-by-step explanation:

In this question, we need to find the cost of 1kg of jelly beans and gummy worms.

To do this, make equations for both scenarios and solve:

2j + 2g = 26

2j + 3g = 33

Turn the bottom equation negative, as we will first solve for gummy worms (g).

2j + 2g = 26

-2j - 3g = -33

Solve:

-g = -7

Divide both sides by -1.

g = 7

We now know that gummy worms cost $7 for 1 kg

To solve for jellybeans (j), plug in 7 to g in one of the equations and solve:

2j + 2(7) = 26

2j + 14 = 26

Subtract 14 from both sides.

2j = 12

Divide both sides by 2.

j = 6

Jellybeans cost $6 for 1 kg.

Check answer by plugging in values to one of the equations:

2(6) + 2(7) = 26

12 + 14 = 26

26 = 26

3 0
3 years ago
What’s the answer to this problem?
Vinil7 [7]

×=23

:) :) :) :) :););) ;););)

5 0
3 years ago
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