Answer: 22 meters
<u>Step-by-step explanation:</u>
Draw a picture of a right triangle and label the height as 30 meters and the hypotenuse as 37 meters. Use the Pythagorean Theorem to find the base (the length of the shadow).
a² + b² = c²
x² + 30² = 37²
x² = 37² - 30²
x² = 1369 - 900
x² = 469
√x² = √469
x = 21.656
x ≈ 22
Answer:
x = - 8, x = 6
Step-by-step explanation:
Given the 2 equations
x² + y² = 100 → (1)
y = x + 2 → (2)
Substitute y = x + 2 into (1)
x² + (x + 2)² = 100
x² + x² + 4x + 4 = 100
2x² + 4x + 4 = 100 ( subtract 100 from both sides )
2x² + 4x - 96 = 0 ( divide through by 2 )
x² + 2x - 48 = 0 ← in standard form
(x + 8)(x - 6) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 8 = 0 ⇒ x = - 8
x - 6 = 0 ⇒ x = 6
Answer:
3rd option
Step-by-step explanation:
Since 8 minutes is included, do the closed circle. He put it in there for 8 minutes, than put it in there for longer which makes the graph go to the right with including the closed circle. Hope this helped!
Grabbing dem points up ✨YeAh✨
Answer:
20 mph
Step-by-step explanation:
Let speed of Train a = Va mph
Let speed of Train b = Vb mph
Va = Vb + 30
Let time taken for Train a = Ta
Let time taken for Train b = Tb
time taken = distance travelled/speed
Ta = 350/Va = 350/(Vb+30)
Tb = 140/Vb
But they both travel in the same amount of time.
So, Ta = Tb
![\frac{350}{v_{b} + 30}=\frac{140}{v_{b}}](https://tex.z-dn.net/?f=%5Cfrac%7B350%7D%7Bv_%7Bb%7D%20%2B%2030%7D%3D%5Cfrac%7B140%7D%7Bv_%7Bb%7D%7D)
Cross multiply
![350v_{b} = 140(v_{b} + 30)\\\\350v_{b} = 140v_{b} + 4200\\\\350v_{b} -140v_{b} = 4200\\\\210v_{b} = 4200](https://tex.z-dn.net/?f=350v_%7Bb%7D%20%3D%20140%28v_%7Bb%7D%20%2B%2030%29%5C%5C%5C%5C350v_%7Bb%7D%20%3D%20140v_%7Bb%7D%20%2B%204200%5C%5C%5C%5C350v_%7Bb%7D%20-140v_%7Bb%7D%20%3D%204200%5C%5C%5C%5C210v_%7Bb%7D%20%3D%204200)
Divide both sides by 210
![\frac{210v_{b} }{210} \frac{4200}{210} \\\\v_{b} = 20 mph](https://tex.z-dn.net/?f=%5Cfrac%7B210v_%7Bb%7D%20%7D%7B210%7D%20%5Cfrac%7B4200%7D%7B210%7D%20%5C%5C%5C%5Cv_%7Bb%7D%20%3D%2020%20mph)