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Reika [66]
2 years ago
10

A cube has six sides that are numbered 1 to 6. The sides numbered 1, 3, and 5 are yellow, and the sides numbered 2, 4, and 6 are

orange. What is the probability of rolling the cube and getting a yellow and even number?
0
1/2
1
Mathematics
1 answer:
mr_godi [17]2 years ago
6 0
0, all yellow sides are odd so you get one or the other, not both
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Function 1: y = 4x + 5
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function 1 slope is 4
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Log based question, i just need help with parts b and c
Tanya [424]

Answer:

b) There is translation 3 units to the right and 1 unit up

c) The domain is {x I x > 3}

   The equation of the asymptote is x = 3

Step-by-step explanation:

* Lets revise the rule of the translation

- If the function f(x) translated horizontally to the right  

 by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  

 by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up  

 by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down  

 by k units, then the new function g(x) = f(x) – k

* Now lets solve the problem

b) ∵ f(x) = log_{2} (x-3)+1

∵ The parent function is log_{2} x

∴ x is changed to (x - 3), that means there is a translation 3 units

  to the right

∵ We add the parent function by 1, that means there is a translation

  1 unit up

* There is translation 3 units to the right and 1 unit up

c) To find the domain of the function, find the values of x which

    make the function undefined

∵ log_{2}(0) is undefined

∴ x - 3 can not be 0

∵ x - 3 = 0 ⇒ add 3 to both sides

∴ x = 3

∴ The domain of the function is all real number greater than 3

* The domain is {x I x > 3}

∵ x can not be 3

∴ There is a vertical asymptote, its equation is x = 3

* The equation of the asymptote is x = 3

# Look to the attached graph for more understand for the domain

  and the equation of the asymptote

4 0
3 years ago
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