Answer:
Step-by-step explanation:
since AD is a median it implies that triangle ABC is bisected to two equal right angled triangle which are ADB and ADC.
FE is parrallel to BC and cuts AB at F and AC at E shows that there are two similar triangles formed which are AFE and ABC.
Recall that ADC is a right angled triangle, ED bisects a right angled triangle the the ADE = 
.
Now, Let FD bisect angle ADB,
then ADF = too.
Since AFX is similar to Triangle ABD and that Triangle AEX is similar to Triangle ACD, then EDX is similar to FDX
FDE = ADF + ADE = 
Answer:
Step-by-step explanation:
B. =16x+288x
C. = 1 18 x2+33.52
D.
1752
x
−
162
29
=
−162
29
x+1752
x
=
6(−27x+8468)
29x
=
−162x+50808
29x
F.=
1
12
x+36
Answer: I think it's a
Step-by-step explanation:
Answers:
Angle T = 79 degrees
Angle V = 14 degrees
=========================================================
Work Shown:
T + V = 93
(2x+85) + (5x+29) = 93
7x+114 = 93
7x = 93-114
7x = -21
x = -21/7
x = -3
This x value is used to find each angle mentioned.
- Angle T = 2x+85 = 2(-3)+85 = -6+85 = 79 degrees
- Angle V = 5x+29 = 5(-3)+29 = -15+29 = 14 degrees
As a check, T+V = 79+14 = 93 which confirms our answers.
