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umka2103 [35]
3 years ago
8

The pair of polygons below are similar. Give the scale factor of figure A to figure B

Mathematics
1 answer:
Alexxx [7]3 years ago
7 0

Answer:

which one?

Step-by-step explanation:

which number do you want solved?

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3 years ago
The length of a rectangle is 6 feet more than three times the width of the
Nesterboy [21]

Answer:

<h2>width = 6 feet</h2>

Step-by-step explanation:

let l be the length of the rectangle

let w be the width of the rectangle

The statement

The length of a rectangle is 6 feet more than three times the width of the

rectangle is written as

l = 6 + 3w

From the question

l = 24 feet

Substitute the value into the above formula and solve for the width

That's

24 = 6 + 3w

3w = 24 - 6

3w = 18

Divide both sides by 3

w = 6

Therefore

<h3>width = 6 feet</h3>

Hope this helps you

3 0
3 years ago
If vector c = vector b + vector a, under what circumstance does c = b+a ?
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The sum of the magnitudes will be the magnitude of the sum when the vectors have the same direction.
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3 years ago
Gravel is being dumped from a conveyor belt at a rate of 20 ft3/min, and its coarseness is such that it forms a pile in the shap
vodomira [7]

Answer:

<h2> 0.0526ft/min</h2>

Step-by-step explanation:

Since the gravel being dumped is in the shape of a cone, we will use the formula for calculating the volume of a cone.

Volume of a cone V = πr²h/3

<em>If the diameter and the height are equal, then r = h</em>

V = πh²h/3

V = πh³/3

If the gravel is being dumped from a conveyor belt at a rate of 20 ft³/min, then dV/dt = 20ft³/min

Using chain rule to get the expression for dV/dt;

dV/dt = dV/dh * dh/dt

From the formula above, dV/dh = 3πh²/3

dV/dh =  πh²

dV/dt = πh²dh/dt

20 = πh²dh/dt

To calculate how fast the height of the pile is increasing when the pile is 11 ft high, we will substitute h = 11 into the resulting expression and solve for dh/dt.

20 = π(11)²dh/dt

20 = 121πdh/dt

dh/dt = 20/121π

dh/dt = 20/380.133

dh/dt = 0.0526ft/min

This means that the height of the pile is increasing at  0.0526ft/min

3 0
3 years ago
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