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umka2103 [35]
3 years ago
8

The pair of polygons below are similar. Give the scale factor of figure A to figure B

Mathematics
1 answer:
Alexxx [7]3 years ago
7 0

Answer:

which one?

Step-by-step explanation:

which number do you want solved?

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I Need help please I only have a little bit of time
kvasek [131]

Answer:

30

Step-by-step explanation:

if its asking for inches

6 0
3 years ago
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2(k + 1) = -4(k - 2)​
Misha Larkins [42]

Answer:

1

Step-by-step explanation:

2(k + 1) = -4(k - 2)

2k + 2 = --4k+8

2k+4k=8-2

6k=6

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7 0
3 years ago
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What is the slope of the line that passes through the points listed in the table?
Allisa [31]

Answer:

D. -4

Step-by-step explanation:

the slope formula is

m=(y2-y1)/(x2-x1)

(x2,y2) = (4,7)

(x1, y1) = (5,3)

So (7-3)/(4-5) = 4/-1 = -4

4 0
3 years ago
Albert receives $0.30 per pound for 1 to 49 pounds of glass bottles he recycles. He receives $0.40
Marina86 [1]

Answer:

Yes

Step-by-step explanation:

The amount of money Albert receives is described by the expression

y = \begin{cases}0.30x  & \quad \text{if } 0 \leq x \leq 49 \\0.40x & \quad \text{if } x > 50\\\end{cases}

The graph is shown below.

To determine if the relation is a function,  we can use the vertical line test:  

If a vertical line crosses the graph more than once in any location, the relation is not a function.

We see that at no place will a vertical line intersect the graph more than once.

The relation is a function.

3 0
4 years ago
At the U.S open tennis championship a statistician keeps track of every serve that a player hits during the tournament. The mean
GarryVolchara [31]

Answer:

Step-by-step explanation:

Both 115 and 145 mph are above the mean.  Draw a normal curve and mark these speeds.  115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.

We need to find the area under the standard normal curve between 115 and 145.  This is equivalent to the area under the standard normal curve between z = 1 and z = 3.

I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area:  normalcdf(1, 3) = 0.1573.

The area between z = 1 and z = 3 is 0.1573.  In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.

8 0
3 years ago
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