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Nadya [2.5K]
3 years ago
9

Mitchell has $18 to spend. What is the greatest number of any one item he can buy?

Mathematics
2 answers:
evablogger [386]3 years ago
6 0
He can buy 1800 gum balls that are 1 penny a piece
NISA [10]3 years ago
3 0

He can buy 6 water bottles that are $3 a piece.

You might be interested in
What is the measure of
posledela
The triangle is isosceles so m∠A and m∠C are the same. 

So to find ∠B, we do 74 + 74 + b = 180

148 + b = 180
b = 180 - 148
b = 32

Answer B is the right choice. 
3 0
3 years ago
How do you do this need help
irakobra [83]
LGN I believe. If you look at how the ret part of the match corresponds with the next match, you can correspond the letters based on the other triangles.
7 0
3 years ago
The answer and how you got the answer
olasank [31]

Answer:

\frac{34}{15}

Step-by-step explanation:

we are asked to evaluate

4\tfrac{1}{4}÷1\tfrac{7}{8}

Above we are given mixed fraction which can be converted in proper fraction using formula given below

a\tfrac{b}{c}=\frac{a \times c +b}{c}

Hence

4\tfrac{1}{4}=\frac{4 \times 4 +1}{4}

4\tfrac{1}{4}=\frac{17}{4}

Also

1\tfrac{7}{8}=\frac{1 \times 8 +7}{8}

1\tfrac{7}{8}=\frac{15}{8}

Hence

4\tfrac{1}{4} ÷ 1\tfrac{7}{8}

can be written as

\frac{17}{4} ÷ \frac{15}{8}

Also we know the rule for dividing fraction is as given below

\frac{a}{b} ÷ \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}

Hence

\frac{17}{4} ÷ \frac{15}{8} = \frac{17}{4} \times \frac{8}{15}

=\frac{17 \times 2}{15}

=\frac{34}{15}

8 0
3 years ago
50 points for this answer
rjkz [21]

Hi Pg1310LisaAwesome,

Solution:

= 2/3 + 1/5

= 10/15 + 3/15

= 13/15

Answer:

13/15

7 0
3 years ago
The vet told Jake that his dog, Rocco, who weighed 55 pounds, needed to lose 10 pounds. Jake started walking Rocco every day and
Ilya [14]

Answer: 55-1/2w=p

Step-by-step explanation: 55 is the starting weight. Therefore, you need to subtract  55 by 1/2 (the amount of weight he loses each week) times each week. This will determines the weight- (p).

6 0
3 years ago
Read 2 more answers
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